A sample of size n = 10 is drawn from a population. The data is shown below.7284.8 99.4 117.9 117.986.7 117.9 98.2 107.591What is the range of this data set?range =What is the standard deviation of this data set? (Remember, it is a sample.) Please report the answer withappropriate rounding, reporting 2 more decimal places than the original data. Please, please, please do notcalculate the value by hand.stdev =

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Answered: A sample of size n = 10 is drawn from a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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myopenmath.com The following table shows the number of people that are either 18, 19, 20 or 21 years old, from a sample of 269 people. a) Complete the table. Age 18 19 20 21 Number of people 61 72 59 (b Find the mean for this sample. Give your answer to at least 2 decimal places. (c Find the standard deviation for this sample. Give your answer to at least 2 decimal places. Question Help:Written Example Message instructor Submit Question Jump to Answer
Find the range and the standard deviation (correct to two decimal places). 81, 91, 96, 96, 96 a) standard deviation =
K Use the body temperatures, in degrees Fahrenheit, listed in the accompanying table. The range of the data is 3.6°F. Use the range rule of thumb to estimate the value of the standard deviation. Compare the result to the actual standard deviation of the data rounded to two decimal places, 0.67°F, assuming the goal is to approximate the standard deviation within 0.2°F. Click the icon to view the table of body temperatures. The estimated standard deviation is F. (Round to two decimal places as needed.) Data table ... 98.5 98.2 98.6 98.4 98.8 98.9 99.1 98.6 97.8 97.6 98.4 98.8 97.1 98.1 98.4 98.3 97.5 98.7 99 96.9 97.1 99.2 98 98.9 97.5 99.2 98.3 99.2 97.9 97.7 98.6 98.2 97.2 98.1 97.8 96.8 97.4 98.3 99.9 98.8 99 98.4 98.8 98.6 98 6.8 98.6 98 98.4 98.2 97.6 98.1 97.6 97.1 99 98.1 97.6 99.2 96.3 97.3 97.9 96.9 97.6 97.6 97.5 97.9 98.3 98.5 98.4 98.3 98 7.6 97.5 97.9 98.3 99.3 98.1 98.9 98.1 98.1 98.6 98.2 99 98.8 97.9 98.2 98.4 98.8 98 98.7 97.3 98.1 99.4 97.9 97.9 98.7 98.3 98.3 97.2 97.9…
What’s the area of the shaded region (Round to the four decimal as needed)
The sample mean amount of savings is $
Please answer
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ = $1.638 and standard deviation o = $1.052. Click the icon to view the frequency distribution for the tax rates. The population mean is $ (Round to three decimal places as needed.) book Get more help. C *** Frequency distribution of cigarette tax rates G Search or type URL Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 4.00-4.49 Print Frequency O 7 12 6 6 6 6 3 3 1 Done - X Clear all Check answer
I need range, variance, and standard deviation please with step by step so I can learn.
The range is (Simplify your answer.) The population mean is (Simplify your answer. Round to the nearest tenth as needed.) The population variance is (Simplify your answer. Round to the nearest tenth as needed.) The population standard deviation is (Simplify your answer. Round to the nearest tenth as needed.)
A survey was conducted to determine the amount of time, on average, during a given week SCAD students spend outside of class on class work (projects, homework, and studying). The data shows: 5, 7, 11, 14, 18, 22 (in hours). Calculate the standard deviation by using the appropriate formula. Round your answer to three decimal places.
The IRS claims it takes an average of 3.7 hours to complete a 1040 tax form. Assume the time t the form is normally distributed with a standard deviation of 15 minutes or 0.25 hours. complete Use the Cumulative Z-Score Table to answer the following questions. Write your answer as a percent using 2 decimal places. What percent of people would you expect to complete the form in less than 3.45 hours? What percent of people would you expect to complete the form-in more than 3.45 hours? What percent of people would you expect to complete the form in less than 3.4 hours? What percent of people would you expect to complete the form in more than 3.4 hours? What percent of people would you expect to complete the form between 3.4 and 3.45 hours?
Find the mean and standard deviation for the individualized instruction scores. Scores Individualized Instruction 50 - 59 4 60 – 69 8 70 - 79 6 80 - 89 8 90 - 99 3 Mean = (Round to the nearest hundredth.)

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