A sample of size n = 10 is drawn from a population. The data is shown below. 68.8 86.8 51.8 86.8 42.2 60.1 86.8 77.2 67.4 51.1 What is the range of this data set? range = 44.6 What is the standard deviation of this data set? (Remember, it is a sample.) Please report the answer with appropriate rounding, reporting 2 more decimal places than the original data. Please, please, please do not calculate the value by hand. stdev =
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- Find the standard deviation of the sample data below: 3,5,6,9 (Answer: 1 decimal place) Type your answer... PreviousIn the 1992 presidential election, Alaska's 40 election districts averaged 1993 votes per district for President Clinton. The standard deviation was 584. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( b. Is 1993 a population mean or a sample mean? Select an answer v C. Find the probability that a randomly selected district had fewer than 2053 votes for President Clinton. d. Find the probability that a randomly selected district had between 2074 and 2208 votes for President Clinton. e. Find the 95th percentile for votes for President Clinton. Round your answer to the nearest whole number.Use the magnitudes (Richter scale) of the 120 earthquakes listed in the accompanying data table. Use technology to find the range, variance, and standard deviation. If another value, 8.00, is added to those listed in the data set, do the measures of variation change much? 3.272.452.542.432.752.372.192.421.911.432.851.731.992.322.332.704.742.873.382.722.833.423.952.993.873.473.082.942.703.602.842.373.033.232.593.643.242.662.352.432.813.952.522.922.983.412.272.562.933.162.201.151.934.002.542.832.352.311.522.801.951.602.452.332.081.553.201.491.812.551.662.352.452.082.192.752.002.792.392.671.692.881.841.991.862.561.972.183.671.553.162.461.881.502.793.283.822.752.452.712.541.642.183.032.361.481.922.322.651.411.391.802.242.302.481.732.402.442.482.44
- Please answerConsider the given data set. n = 12 measurements: 9, 8, 1, 5, 5, 7, 5, 6, 8, 7, 2, 0 Find the mean. USE SALT Find the standard deviation. (Round your answer to four decimal places.) z = Find the z-score corresponding to the minimum in the data set. (Round your answer to two decimal places.) Find the z-score corresponding to the maximum in the data set. (Round your answer to two decimal places.) z = Do the z-scores indicate that there are possible outliers in the data set? Since the z-score for the larger observation is larger than 2 in absolute value, the larger value is unusually large. Since both z-scores exceed 2 in absolute value, both of the observations are unusual. Since neither z-score exceeds 2 in absolute value, none of the observations are unusually small or large. Since the z-score for the smaller observation is larger than 2 in absolute value, the smaller value is unusually small.The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance, and standard deviation of the population data set. 2, 9, 15, 4, 15, 6, 12, 8, 5, 9 C The range is 13 (Simplify your answer.) The population mean is 8.5. (Simplify your answer. Round to the nearest tenth as needed.) The population variance is 17.9. (Simplify your answer. Round to the nearest tenth as needed.) The population standard deviation is. (Simplify your answer. Round to the nearest tenth as needed.)
- n the 1992 presidential election, Alaska's 40 election districts averaged 2111 votes per district for President Clinton. The standard deviation was 551. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 2111 a population mean or a sample mean? Select an answer Population Mean Sample Mean c. Find the probability that a randomly selected district had fewer than 2134 votes for President Clinton. d. Find the probability that a randomly selected district had between 2048 and 2241 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.506 and standard deviation o = $1.004. Click the icon to view the frequency distribution for the tax rates. Frequency distribution of cigarette tax rates Tax Rate Frequency 0.00–0.49 7 0.50-0.99 14 1.00–1.49 7 1.50–1.99 2.00–2.49 5 2.50–2.99 5 3.00–3.49 3.50–3.99 1 4.00-4.49 1Use the magnitudes (Richter scale) of the 120 earthquakes listed in the accompanying data table. Use technology to find the range, variance, and standard deviation. If another value, 8.00, is added to those listed in the data set, do the measures of variation change much? 3.30 2.77 2.80 1.96 1.69 2.54 2.43 3.44 3.92 1.58 2.87 1.63 2.56 3.95 2.50 2.44 1.82 2.19 2.44 2.99 2.92 2.35 1.98 3.06 2.78 3.86 2.95 2.07 1.86 2.36 2.37 3.46 3.45 1.54 2.54 1.49 2.22 3.06 2.27 3.20 1.96 1.91 2.40 2.95 2.61 1.49 2.16 2.33 1.91 2.70 2.92 1.80 3.66 2.69 1.43 3.60 3.13 2.56 1.54 1.41 2.83 2.85 2.20 1.68 3.18 1.38 1.73 2.37 1.15 2.35 2.46 1.81 2.01 3.00 1.94 2.42 1.85 2.24 2.35 3.22 3.97 2.10 1.48 2.31 2.31 2.62 2.55 2.20 2.77 2.46 2.69 3.57 2.84 2.75 3.26 1.74 4.72 3.23 2.36 2.00 3.83 2.41 2.88 2.67 2.32 2.80 2.80 2.40 3.41 2.34 1.49 2.41 2.45 2.50 2.73 2.44 2.78 2.65 2.68 2.43 Without the extra data value, the range is 3.573.57. (Type an integer or…
- A sample of 6 sheets of cardstock is randomly selected and the following thicknesses are measured in millimeters. Give a point estimate for the population standard deviation. Round your answer to three decimal places. 1.82, 1.67, 1.87, 1.79, 1.79, 1.73In the 1992 presidential election, Alaska's 40 election districts averaged 1989 votes per district for President Clinton. The standard deviation was 568. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( __ , __ ) b. Is 1989 a population mean or a sample mean? Select an answer _______. c. Find the probability that a randomly selected district had fewer than 2087 votes for President Clinton. _____ d. Find the probability that a randomly selected district had between 1905 and 2194 votes for President Clinton.______ e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number. ______Please help me with this question.