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A sample of pure NO2NO2 is heated to 339 ∘C∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+O2(g)2NO2(g)⇌2NO(g)+O2(g) At equilibrium the density of the gas mixture is 0.520 g/Lg/L at 0.750 atmatm . Calculate Kc for the reaction.

A sample of pure NO2NO2 is heated to 339 ∘C∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+O2(g)2NO2(g)⇌2NO(g)+O2(g) At equilibrium the density of the gas mixture is 0.520 g/Lg/L at 0.750 atmatm . Calculate Kc for the reaction.

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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A sample of pure NO2NO2 is heated to 339 ∘C∘C at which temperature it partially dissociates according to the equation
2NO2(g)⇌2NO(g)+O2(g)2NO2(g)⇌2NO(g)+O2(g)
At equilibrium the density of the gas mixture is 0.520 g/Lg/L at 0.750 atmatm .

Calculate Kc for the reaction.

Expert Solution
Step 1: Determine the equilibrium constant for the reaction from the given data:

G i v e n comma T h e space d e c o m p o s i t i o n space r e a c t i o n colon 2 space N O subscript 2 space left parenthesis g right parenthesis end subscript space rightwards harpoon over leftwards harpoon space 2 space N O subscript left parenthesis g right parenthesis end subscript space plus space O subscript 2 space left parenthesis g right parenthesis end subscript A t space e q u i l i b r i u m comma space d e n s i t y space o f space g a s space m i x t u r e space equals space 0.520 space g over L p r e s s u r e space equals space 0.750 space a t m

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