A sample of pure saponin is purchased and a 0.1 vol% solution in water is prepared. A series of dilutions are needed to prepare a calibration curve for erythrocyte lysis. Complete the following data table by filling in the missing values. A 5-mL aliquot of each solution (having different concentrations) will be needed. Using your 0.1 vol% standard solution, calculate what volume (µL) of the standard solution and what volume of water (mL) will need to be mixed together to make a 5.000 mL solution of the indicated concentration. Solution Concentration Volume of Volume of Final volume 0.1 vol% saponin (µL) desired dilution solvent (mL) (vol%) (mL) 1 0.05 5.000 0.01 5.000 3 0.005 5.000 4 0.0025 5.000 5 0.001 5.000 6 0.0006 5.000 Hint: Use CiV1= C2V2, where Ci is the standard concentration, Vi is the associated volume of the standard needed, C2 is the concentration desired for each solution, and V2 is the final volume for each solution.

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Chapter1: Chemical Foundations
Section: Chapter Questions
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This comes from Quantitative Chemistry and the textbook is Analytical Chemistry. Please at least solve the table, if not the essay question.

Saponin is a mixture of similar chemical compounds that can be extracted from various natural
sources, for example, the bark of a tree. A mixture of saponins can be purchased commercially
and solutions of saponin are often used as positive controls in erythrocyte lysis assays.
What is an erythrocyte lysis assay?
A sample of pure saponin is purchased and a 0.1 vol% solution in water is prepared. A series of
dilutions are needed to prepare a calibration curve for erythrocyte lysis. Complete the following
data table by filling in the missing values. A 5-mL aliquot of each solution (having different
concentrations) will be needed. Using your 0.1 vol% standard solution, calculate what volume
(µL) of the standard solution and what volume of water (mL) will need to be mixed together to
make a 5.000 mL solution of the indicated concentration.
Solution
Concentration
Volume of
Volume of
Final volume
0.1 vol% saponin
(µL)
desired
dilution solvent
(mL)
(mL)
(vol%)
0.05
1
5.000
0.01
5.000
3
0.005
5.000
4
0.0025
5.000
5
0.001
5.000
0.0006
5.000
Hint: Use CiVi= C2V2, where Cı is the standard concentration, Vi is the associated volume of
the standard needed, C2 is the concentration desired for each solution, and V2 is the final volume
for each solution.
2.
Transcribed Image Text:Saponin is a mixture of similar chemical compounds that can be extracted from various natural sources, for example, the bark of a tree. A mixture of saponins can be purchased commercially and solutions of saponin are often used as positive controls in erythrocyte lysis assays. What is an erythrocyte lysis assay? A sample of pure saponin is purchased and a 0.1 vol% solution in water is prepared. A series of dilutions are needed to prepare a calibration curve for erythrocyte lysis. Complete the following data table by filling in the missing values. A 5-mL aliquot of each solution (having different concentrations) will be needed. Using your 0.1 vol% standard solution, calculate what volume (µL) of the standard solution and what volume of water (mL) will need to be mixed together to make a 5.000 mL solution of the indicated concentration. Solution Concentration Volume of Volume of Final volume 0.1 vol% saponin (µL) desired dilution solvent (mL) (mL) (vol%) 0.05 1 5.000 0.01 5.000 3 0.005 5.000 4 0.0025 5.000 5 0.001 5.000 0.0006 5.000 Hint: Use CiVi= C2V2, where Cı is the standard concentration, Vi is the associated volume of the standard needed, C2 is the concentration desired for each solution, and V2 is the final volume for each solution. 2.
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