A sample of only calcium chloride (CaCl2 110.99 g/mol) and potassium chloride (KCl 74.55 g/mol) is analyzed for the chloride content by adding excess silver nitrate. If 5.00 g of the sample gives 12.4 g silver chloride precipitate (AgCl 143.32 g/mol), what is the percentage of chloride in the original sample?

Q: A 155.0 mL solution of 2.661 M strontium nitrate is mixed with 215.0 mL of a 2.464 M sodium fluoride…

A:

Q: Barium hydroxide is mixed with lithium phosphate at room temperature.   If 10.0 g of barium…

A: Mass of barium hydroxide = 10.0 g  Molarity of Lithium phosphate = 0.500 mol / L We need to…

Q: What mass of precipitate is formed when 100. mL of  0.350 M  NaCl reacts with  100. mL  of  0.175 M…

A: When an insoluble substance is present in the chemical solution it is called a precipitate.…

Q: A 0.702 g0.702 g mixture containing only sodium chloride and potassium chloride was dissolved in…

A: First calculate mole of each substance by dividing molar mass to the mass then calculate mole of…

Q: A solution contains Cr*ions and Mg*+ ions. The addition of 1.00 L of 1.51 M NaF solution causes the…

A: Given that : Volume of NaF added = 1L Molarity of NaF = 1.51M The total mass of precipitate = 49.6g…

Q: Suppose 23.0 mL of 0.190 M CoCl₂ solution is added to 26.0 mL of 0.430 M NiCl₂ solution. Calculate…

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Q: The Burke Museum at the UW is analyzing a dinosaur bone sample for the amount of calcium it…

A: The solid

Q: Calculate the mass of precipitate formed when 35.0 mL of a 0.155 M NaBr solution is added to 25.5 mL…

A: Given, For NaBr solution Concentration of NaBr solution = 0.155 M = 0.155 mol/L Volume of NaBr…

Q: If 30.0 mL of 0.150 M CaCl₂ is added to 16.0 mL of 0.100 M AgNO3, what is the mass of the AgCl…

A: The question is based on the concept of reaction stoichiometry.We need to calculate mass of…

Q: 471 mL of 2.013 M linthium baltimide (LiBr, 84.781 g/mol) is combined with 380 mL of 6.582 M shorium…

A: Calculation

Q: A 0.5000 g sample of a pesticide (DDT, C14H9Cl5, MM 354.49 g/mol) was decomposed with metallic…

A: Number of moles of Cl in AgCl will be same as in DDT. This is due to the fact that mass is…

Q: Calculate the volume (in mL) of 0.100 M CaCl₂ needed to produce 1.00 g of . There is an excess of…

A: Molarity of CaCl2 = 0.100 MMass of CaCO3 = 1.00 gMolar mass of CaCO3 = 100.09 g/mol

Q: Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are…

A: NH4NO3 + NaOH → NaNO3 + NH3•H2O. There is no precipitation takes place during this reaction.  2)Yes,…

Q: If 50.0 g of CH₂OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Given,the mass of CH3OH = 50.0 gmolar mass of CH3OH = 32.04 g/molvolume of the water ( solution ) =…

Q: You are given solutions of HCl and NaOH and must determine their concentrations. You use 27.5 mL of…

A: Given :             27.5 mL of NaOH to titrate 100.0 mL of HCl             18.4 mL of NaOH to…

Q: If 50.0 g of CH₃OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Number of moles =50.0 g/32.04 g/mol                                      =1.56 mol

Q: 3. A solution is prepared by mixing 43.0 mL of a 0.174 M NaCl solution with 30.0 mL of a 0.261 M…

A: Given Volume of NaCl= 43.0 ml Molarity of NaCl= 0.174 M Volume of CaCl2= 30 ml Molarity of CaCl2 =…

Q: What mass of precipitate is formed when 100. mL of  0.350 M  NaCl reacts with  100. mL  of  0.175 M…

A: In this question, we have to find out the correct answer of given problem by the help of the…

Q: The percentage of NaHCO3 (molar mass = 84.01 g) in a powder used for an upset stomach is found by…

A:

Q: When 3.5 g of CaF2 (an insoluble salt, Ksp = 3.9 X 10-11) is added to water to make 200. mL of…

A: mole  = mass  /  molecular weight molecular weight of CaF2 = 78.07 g/mole concentration = mole  *…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 24.0 mL of…

A: Cu(NO₃)₂ + 2 NaOH = Cu(OH)2 + 2 NaNO3. From the above chemical equation we can see that , 1 mol…

Q: Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are…

A:

Q: A solution is prepared by mixing 25.0 mL of a 0.150 M potassium chloride (KCl) with 75.0 mL of a…

A: In this question we have to tell the molarity of K+ ions in the solution.

Q: 0.8838-g sample of an ionic compound containing bromide ions and an unknown metal cation is…

A: Weight of ionic compound = 0.8838 gm Weight of precipitate (AgBr) = 1.573 gm

Q: A student was given a 3.708-g sample of a mixture of potassium nitrate and potassium bromide and was…

A: Given ; Mass of sample = 3.708 g Mass of AgBr precipitate formed = 2.957 g And the sample contains…

Q: A combination of Planet X elements (vibranium and bazoolium) and Earth elements are being studied in…

A: Given data,Molarity of V(NO3)2=0.60MVolume of V(NO3)2=142.5mL=0.1425LMolarity of BzI=0.80MVolume of…

Q: solution contains dissolved Ag+ ions. The valuable silver ions can be recovered from this solution…

A: Given:Volume of AgNO3 solution, V1= 100ml…

Q: formula in the last column. solution A iron(II) bromide copper(II) chloride zinc nitrate solution B…

A: 1. FeBr2(aq) + 2NaOH (aq) ---->  2. CuCl2(aq) + (NH4)2S (aq) ---->  3. Zn(NO3)2(aq) +…

Q: If 150.0 mL of 2.5 mol/L Na2SO4 is mixed with 125 mL of 0.26 mol/L AgNO3, determine the…

A: A question based on mole concept that is to be accomplished.

Q: Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are…

A:

Q: What is the maximum mass (in grams) of precipitate that can form when 150.0 mL of 0.1250 M of barium…

A: Given,molarity of barium bromide = 0.1250 MVolume of barium bromide = 150.0 mLMolarity of…

Q: A combination of Planet X elements (vibranium and bazoolium) and Earth elements are being studied in…

A: According to the law of chemical equivalence, in a chemical reaction, the number of equivalents that…

Q: A 2.50 g sample of a group 3A metal chloride, MCl3, is mixed with excess AgNO3. The mass of the AgCl…

A: Chemical Reaction =>  AgNO3 + MCl3  ---> 3AgCl  + M(NO3)3  A 2.50 g  3A metal chloride (MCl3)…

Q: The calcium in a 300.0 ml sample of natural water was determined by precipitating the cation as…

A: Answer: This question is based on stoichiometric calculation where we have to find out the number of…

Q: If 25.0 mL of 0.120 M Na3PO4 and 30.0 mL of 0.110 M CaCl2 are mixed, what precipitate forms?  Write…

A:

Q: If 23.9 g of CH₃OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Molarity (M) is a concentration term for a solution. The molarity of the given solution is defined…

Q: If 25.2 mL of AgNO3 is needed to precipitate all the Cl ions in a 0.775-mg sample of KCI (forming…

A:

Q: The concentration of a certain sodium hydroxide solution was determined by using the solution to…

A: Given: Volume of NaOH neutralized = 48.82 mL = 0.04882 L                           (Since 1 L = 1000…

Q: A 1.3685-g a chloride-containing sample was analyzed by precipitating 0.4713 grams of AgCl (MW =…

A: Mass of sample = 1.3685 gram  Precipitation = 0.4713 gram To find = mass percentage of chloride

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.