A sample of O2 gas is observed to effuse through a porous barrier in 7.64 minutes. Under the same conditions, the same number of moles of an unknown gas requires 12.7 minutes to effuse through the same barrier. The molar mass of the unknown gas is g/mol.

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Chapter1: Chemical Foundations
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A sample of O2 gas is observed to effuse through a porous barrier in 7.64 minutes. Under the same conditions, the same number of moles of an unknown gas requires 12.7 minutes to effuse through the same barrier.

The molar mass of the unknown gas is g/mol.

Expert Solution
Step 1: Graham's law of effusion

Effusion is the process of movement of gaseous molecules through a small hole. The rate of effusion is inversely proportional to the square root of the molar mass of the gas, that is, the higher the molar mass, the slower will be the effusion and its vice-versa.

The rate of effusion is also inversely proportional to the time of effusion. The relationship between effusion rate, molar mass, and time of effusion can be given as:

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