A sample of methane gas (CH4) at 15.7 °C is either heated or cooled. The pressure increases from 1.29 atm to 3.87 atm, and the volume of the sample changes from 4.89 L to 4.91L To what temperature, in °C, was the methane heated or cooled? Answer:
A sample of methane gas (CH4) at 15.7 °C is either heated or cooled. The pressure increases from 1.29 atm to 3.87 atm, and the volume of the sample changes from 4.89 L to 4.91L To what temperature, in °C, was the methane heated or cooled? Answer:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
A sample of methane gas (CH₄) at 15.7°C is either heated or cooled. The pressure increases from 1.29 atm to 3.87 atm, and the volume of the sample changes from 4.89 L to 4.91 L. To what temperature, in °C, was the methane heated or cooled?
**Answer:**
[Provide Calculation and Final Temperature Here]
**Explanation:**
To solve this problem, you can use the combined gas law, which relates pressure (P), volume (V), and temperature (T) of a gas:
\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \]
Where:
- \(P_1 = 1.29\) atm
- \(V_1 = 4.89\) L
- \(T_1 = 15.7 + 273.15\) K (convert Celsius to Kelvin)
- \(P_2 = 3.87\) atm
- \(V_2 = 4.91\) L
- \(T_2 = ?\) K (the temperature you need to find)
Rearrange the equation to solve for \(T_2\) and convert the final temperature back to Celsius by subtracting 273.15.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3925343-d6c3-4a25-992b-202f02b2b634%2F3053f95d-f7f9-4ff3-b3de-2d99e1997c56%2F81bw7d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A sample of methane gas (CH₄) at 15.7°C is either heated or cooled. The pressure increases from 1.29 atm to 3.87 atm, and the volume of the sample changes from 4.89 L to 4.91 L. To what temperature, in °C, was the methane heated or cooled?
**Answer:**
[Provide Calculation and Final Temperature Here]
**Explanation:**
To solve this problem, you can use the combined gas law, which relates pressure (P), volume (V), and temperature (T) of a gas:
\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \]
Where:
- \(P_1 = 1.29\) atm
- \(V_1 = 4.89\) L
- \(T_1 = 15.7 + 273.15\) K (convert Celsius to Kelvin)
- \(P_2 = 3.87\) atm
- \(V_2 = 4.91\) L
- \(T_2 = ?\) K (the temperature you need to find)
Rearrange the equation to solve for \(T_2\) and convert the final temperature back to Celsius by subtracting 273.15.
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