A sample of methane gas (CH4) at 15.7 °C is either heated or cooled. The pressure increases from 1.29 atm to 3.87 atm, and the volume of the sample changes from 4.89 L to 4.91L To what temperature, in °C, was the methane heated or cooled? Answer:

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
**Problem Statement:**

A sample of methane gas (CH₄) at 15.7°C is either heated or cooled. The pressure increases from 1.29 atm to 3.87 atm, and the volume of the sample changes from 4.89 L to 4.91 L. To what temperature, in °C, was the methane heated or cooled?

**Answer:**

[Provide Calculation and Final Temperature Here]

**Explanation:**

To solve this problem, you can use the combined gas law, which relates pressure (P), volume (V), and temperature (T) of a gas:

\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \]

Where:
- \(P_1 = 1.29\) atm
- \(V_1 = 4.89\) L
- \(T_1 = 15.7 + 273.15\) K (convert Celsius to Kelvin)
- \(P_2 = 3.87\) atm
- \(V_2 = 4.91\) L
- \(T_2 = ?\) K (the temperature you need to find)

Rearrange the equation to solve for \(T_2\) and convert the final temperature back to Celsius by subtracting 273.15.
Transcribed Image Text:**Problem Statement:** A sample of methane gas (CH₄) at 15.7°C is either heated or cooled. The pressure increases from 1.29 atm to 3.87 atm, and the volume of the sample changes from 4.89 L to 4.91 L. To what temperature, in °C, was the methane heated or cooled? **Answer:** [Provide Calculation and Final Temperature Here] **Explanation:** To solve this problem, you can use the combined gas law, which relates pressure (P), volume (V), and temperature (T) of a gas: \[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \] Where: - \(P_1 = 1.29\) atm - \(V_1 = 4.89\) L - \(T_1 = 15.7 + 273.15\) K (convert Celsius to Kelvin) - \(P_2 = 3.87\) atm - \(V_2 = 4.91\) L - \(T_2 = ?\) K (the temperature you need to find) Rearrange the equation to solve for \(T_2\) and convert the final temperature back to Celsius by subtracting 273.15.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY