A sample of gas has a volume of 7.00 L and a pressure of 2.750 kPa when its temperature is 45.0°C. If the volume is expanded to 14.00 L and the pressure °C? (Round reduced to 1.500 kPa. The new temperature would become off the new temperature to nearest whole number).

Q: Use the References to access important values if needed for this question. STP (standard temperature…

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Q: An ideal gas in a sealed container has an initial volume of 2.55 L. At constant pressure, it is…

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Q: 15.0 L of an ideal gas at 298.0 K and 3.36 bar are heated to 350.0 K with a new pressure of 2.70…

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Q: A sample of helium at 20 °C occupies a volume of 7.90 L at a pressure of 6.32 atm. What volume does…

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Q: A particular gas has an initial volume of 2.27 L and an initial temperature of 162.7 K. If the…

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Q: 15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 6.15 atm.…

A: using the ideal gas law equation to find the new volume.

Q: 15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.30 atm.…

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A: #1) Given,Initial temparature (T1) = 22oC = (22 + 273) K = 295 KInitial volume (V1) = 12.8 LFinal…

Q: 2. A sample of molecular nitrogen gas, N2, occupies 3.0 L at a pressure of 3.0 atm. What volume will…

A: The volume of the sample is = 3.0 L The initial pressure of the sample is = 3.0 atm The final…

Q: 15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 6.45 atm.…

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A: Introduction: Combined gas law is the combination of Boyle's law, Charle's law and Gay-Lussac's law.…

Q: A 0.530 mol sample of carbon dioxide gas occupies a volume of L at STP.

A: STP refers to standard temperature and pressure conditions. At STP, the standard temperature is 0oC…

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A: The question is based on the concept of physical chemistry. we have to calculate the amount of air…

Q: If 3.97 Mol of an ideal gad has a pressure of 3.07 atm and a volume of 34.35 L, what is the…

A: For ideal gas PV= nRT p= pressure V=volume n= no. of moles R= gas constant T= temperature

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Q: A sample of carbon dioxide gas at a pressure of 1.07 atm and a temperature of 166° C, occupies a…

A: According to ideal gas law, PV = nRT where P = pressure V = volume n = moles R = gas constant T =…

Q: 15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.45 atm.…

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Q: Under 5.0 atm at 298 K, a gas sample takes up 6.0 mL. When placed in a volume of 3.0 mL at 298 K,…

A: Given: Given: Initial Pressure, P1=5.0 atm The initial volume, V1= 6.0 mL The initial temperature,…

Q: 13.) a) A climber takes a large balloon with 5.0 mol of ideal gas to the top of Mount Everest, where…

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Q: None

A: Step 1:To find the final pressure of the nitrogen gas after the temperature and volume changes, we…

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A: Given data : Initial temperature(T1) = -12.0°C = (-12+273)K = 261 K Final temperature (T2) = 13.0°C…

Q: Please don't provide handwritten solution ....

A: P2=4.34atmPlease find the below attached solution of problem given,feel free to ask any further…

Q: A sample of gas at 867.5 mmHg, occupying a volume of 13.64 L, and at a temperature of 20.80 °C is…

A: P1 = 867.5mmHg V1 = 13.64L T1 = 20.80oC = 293.95K P2 =  255.09kPa = 1913.33207mmHg T2 = 74.66oC =…

Q: 247.2 liters of gas has a pressure of 128.02 kPa at 57.5 C.  If the pressure increases to 577.0 kPa…

A: For an ideal gas: PV = nRT => PV/T = nR where n, moles of gas and R, gas constant. P is pressure…

Q: 15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.45 atm.…

A: Given data of the following, V1=15.0 L, T1=298 K, P1=3.36 atm V2= ?, T2=383 K, P2=5.45 atm

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A: Given,Initial moles of a gas inside the cylinder ( n1 ) = 2.10 molInitial volume of a gas inside the…

Q: The volume of an automobile tire is 2.5 × 10−2m3 . the pressure of the air in the tire is  3.1 atm…

A: Given: Volume of tire = 2.5 X 10-2 m3 = 25 L                                          (Since 1 m3 =…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.