A sample of dry sand is tested in direct shear. The shear box holding the sample has a circular cross section with a diameter of 50 mm. The normal (compressive) load imposed is 200 N. The sample shears when the shear force is 130 N. (a) Determine the test normal stress and shear
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- 3. In a drained tri-axial test, a specimen is confined under pressure and axially loaded until failure. The failure conditions of the specimen are analyzed for shear strength. What is the value of the minor principle stress? Half the value of the major principle stress Twice the value of the major principle stress . The same as the confining pressure The same as the cohesion value ● ● ●Assume that both a triaxial shear test and a direct shear test are to be performed on a sample of dry sand. When the triaxial shear test is performed, the specimen fails when the major and minor principal stresses are 80 and 20 lbs/in^2, respectively. When the direct shear test is performed, what shear strength can be expected if the normal stress is 4000 lbs/ft^2? Show all work.A specimen is subjected to a tri-axial test. The soil specimen is cohesionless. If the shear stress that cause failure is 3oo kPa and the normal stress at failure is only 475 kPa. 1. Determine the angle of shearing resistance. 2.Determine the angle that the failure plane measured from the major principal plane 3.Determine the maximum principal stress at which failure is expected to occur
- In a direct shear test on a specimen of cohesionless soil (sand), the vertical normal stress on the specimen is 210 kPa and the horizontal shear stress at failure is 135 kPa. You may assume the uniform stress distribution within the failure zone. a) determine the magnitude and direction of the principal stresses at failure using a Mohr's circle b) briefly explain whether it's possible to determine the magnitude and direction of the principal stresses when the material is not failed.A sample of dry sand is tested in direct shear. Theshear box holding the sample has a circular crosssection with a diameter of 50 mm. The normal(compressive) load imposed is 200 N. The sam-ple shears when the shear force is 130 N.(a) Determine the test normal stress and shearstress at failure.(b) Determine the angle of internal frictionfor this soil.(c) What is the probable condition of the testedsample (dense, loose, etc.)?Assume that both a triaxial shear test and a direct shear test are to be performed on a sample of dry sand. When the triaxial shear test is performed, the specimen fails when the major and minor principal stresses are 80 and 20lb/in2, respectively. When the direct shear test is performed, what shear strength can be expected if the normal stress is 4000 lb/ft2? Kindly get right answer with explaination steps
- Assume that both a triaxial shear test and a direct shear test are to be performed on a sample of dry sand. When the triaxial shear test is performed, the specimen fails when the major and minor principal stresses are 80 and 20 lb/in.2, respectively. When the direct shear test is performed, what shear strength can be expected if the normal stress is 4000 lb/ft2?8. A cohesionless (c' = 0 kPa) soil specimen was subjected to a consolidated-undrained triaxial test. The total stress path, the deviator stress, and the pwp are shown in the figures below. No scale is intended in the figure of the stress path. a. Determine o'₁ and 0's at failure. [o'₁ = 345 kPa, o's= 140 kPa] b. Determine the effective friction angle (') of the soil. [$' = 25°] C. Determine the 'A' pore water pressure parameter at failure. [A+ = 0.29] 250 -Deviator Stress q (kPa), 200 150 100 50 200 p (kPa) Deviator stress or PW/P (kPa) 5 10 Vertical strain (%) ---PWP 15 20A sample of sand is sheared in the following manner. First an all around normal stresso 350 kPa is applied to the sample. Next a shear stress is applied to the horizontal pia while the normal stress remains constant. The shear stresses at failure are + 186 kPa. Ihe initial stress and stress condition at failure are shown below 350 kPa 350 kPa 186 kPa 350 kPa 350 kPa ー550 kPa 550 kPa 186 kPa 350 kPa 350 kPa Initial Conditions At Failure Determine the Following: fo A) Assuming c, = 0, draw a failure envelope for the soil. Define the friction angle ( the soil. B) Draw the Mohr's Circle at failure for the test. C) Show the location of the pole. D) Define the maximum and minimum principal stresses at failure. E) Define the normal stress corresponding to the maximum shear stress
- A sand sample is subjected to direct shear testing. Two tests areperformed. For test 1, The sample shears at a stress of 2500 psf whenthe normal stress is 4000 psf.Test 2, The sample shears at a stress of 3500 psf when the normalstress is 6000 psf. Determine the following:a) Angle of Internal frictionb) Value of cohesionc) Compute the shear stress at a depth of 12 ft. if the unit weight ofthe soil is 150 pcfA CID TXC test was performed on a sample of sand. At the end of consolidation, the back pressure was 140 kPa, and the cell pressure was 340 kPa. At failure, the deviator stress was (ơ1 – 03)f = 200 kPa. a. What was the total pore water pressure, u, at failure? b. Calculate the principle effective stresses, ơi' and os', at failure. c. Calculate the friction angle, d', for this soil.A direct shear test is performed on a specimen of dry sand. The shear box is circular in cross-section with a diameter of 50 mm. The normal force imposed on the specimen is 250 N. Then shears when the shear force is 150 N. Determine the angle of internal friction of this sand.