A sample of argon gas has a volume of 735 mL at a pressure of 1.20 atm and a temperature of 112 °C. What is the final volume of the gas, in milliliters, when the pressure and temperature of the gas sample are changed to the following, if the amount of gas does not change? You may want to reference (Pages 289 - 290) Section 8.5 while completing this problem.

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**Gas Laws Application: Volume Calculation**

A sample of argon gas has a volume of 735 mL at a pressure of 1.20 atm and a temperature of 112°C. What is the final volume of the gas, in milliliters, when the pressure and temperature of the gas sample are changed to the following, if the amount of gas does not change?

You may want to reference [Pages 289 - 290] Section 8.5 while completing this problem.

---

**Explanation:**

The problem is likely related to the ideal gas law or combined gas law, where you need to adjust the volume of a gas based on changes in temperature and pressure while keeping the amount of gas constant. Calculations will involve using formulas to determine the final volume under the new conditions.
Transcribed Image Text:**Gas Laws Application: Volume Calculation** A sample of argon gas has a volume of 735 mL at a pressure of 1.20 atm and a temperature of 112°C. What is the final volume of the gas, in milliliters, when the pressure and temperature of the gas sample are changed to the following, if the amount of gas does not change? You may want to reference [Pages 289 - 290] Section 8.5 while completing this problem. --- **Explanation:** The problem is likely related to the ideal gas law or combined gas law, where you need to adjust the volume of a gas based on changes in temperature and pressure while keeping the amount of gas constant. Calculations will involve using formulas to determine the final volume under the new conditions.
### Part C

14.9 atm and -13°C

Express your answer with the appropriate units.

\[ V = \text{Value} \quad \text{Units} \]

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Multiplying the initial and final pressure values together would result in units of atm². Rearrange the combined gas law to solve for the final volume \( V_2 \):

\[ \frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \]

Where:
- \( P_1 \) is the initial pressure,
- \( V_1 \) is the initial volume,
- \( T_1 \) is the initial temperature,
- \( P_2 \) is the final pressure,
- \( T_2 \) is the final temperature.

All temperature values must be in kelvins to use this equation.

You may need to review [Rearrangement of Equations Involving Multiplication and Division](#).

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Transcribed Image Text:### Part C 14.9 atm and -13°C Express your answer with the appropriate units. \[ V = \text{Value} \quad \text{Units} \] **Submit Buttons:** - Submit - Previous Answers - Request Answer --- **Feedback Section** ❌ **Incorrect; Try Again; 5 attempts remaining** Multiplying the initial and final pressure values together would result in units of atm². Rearrange the combined gas law to solve for the final volume \( V_2 \): \[ \frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \] Where: - \( P_1 \) is the initial pressure, - \( V_1 \) is the initial volume, - \( T_1 \) is the initial temperature, - \( P_2 \) is the final pressure, - \( T_2 \) is the final temperature. All temperature values must be in kelvins to use this equation. You may need to review [Rearrangement of Equations Involving Multiplication and Division](#). **Footer** - Provide Feedback - © 2021 Pearson Education Inc. All rights reserved. - Terms of Use | Privacy Policy | Permissions | Contact Us ---
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