A sample of 1H in the equilibrium condition in a static magnetic field BO is excited by a short circularly polarized RF pulse.The RF pulse is a magnetic field in the transverse planeB₁(t) = B₁(t)e-i²πvot G₂where vo is the Larmor frequency of the sample. The envelope of the RF pulse is a triangle function with parameter T:(1-7), 0≤t≤2TotherwiseB₁ (t)=={0,(a) Find the tip angle of the magnetization vector as a function of t for 0 ≤ t ≤ 2T.(b) What is the value of T to make B1(t) a π/2 pulse?

Answered: Image /qna-images/answer/df409be9-78e9-42fc-bb2a-b9dafdd8c0e3.jpg

Answered: A sample of 1H in the equilibrium…

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