A sample of 16 ten-year-old girls had a mean weight of 71.5 and a standard deviation of 12 pounds, respectively. Assuming normality, find the 90 percent confidence intervals for mean the lower limit is ....
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- A survey found that women's heights are normally distributed with mean 62.3 in. and standard deviation 2.8 in. The survey also found that men's heights are normally distributed with mean 68.5 in. and standard deviation 3.7 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 57 in. and a maximum of 62 in. Complete parts (a) and (b) below. a. Find the percentage of men meeting the height requirement. What does the result suggest about the genders of the people who are employed as characters at the amusement park? The percentage of men who meet the height requirement is %. (Round to two decimal places as needed.)Use the following information to answer the question. The mean age of lead actresses from the top ten grossing movies of 2010 was 29.6 years with a standard deviation of 6.35 years. Assume the distribution of the actresses' ages is 4) Between what two values would you expect to find about 95% of the lead actresses ages? a approximately unimodal and symmetric.A survey found that women's heights are normally distributed with mean 62.4 in. and standard deviation 3.7 in. The survey also found that men's heights are normally distributed with mean 69.6 in. and standard deviation 3.7 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 56 in. and a maximum of 64 in. Complete parts (a) and (b) below. a. Find the percentage of men meeting the height requirement. What does the result suggest about the genders of the people who are employed as characters at the amusement park? The percentage of men who meet the height requirement is 6.50 %. (Round to two decimal places as needed.) Since most men do not meet the height requirement, it is likely that most of the characters are women. b. If the height requirements are changed to exclude only the tallest 50% of men and the shortest 5% of men, what are the new height requirements? The new height requirements are a minimum of in. and a maximum of in. (Round…
- You are interested in estimating the the mean weight of the local adult population of female white-tailed deer (doe). From past data, you estimate that the standard deviation of all adult female white-tailed deer in this region to be 23 pounds. What sample size would you need to in order to estimate the mean weight of all female white-tailed deer, with a 96% confidence level, to within 4 pounds of the actual weight?Sample Size: ????Use z scores to compare the given values. Based on sample data, newborn males have weights with a mean of 3282.4 g and a standard deviation of 704.5 g. Newborn females have weights with a mean of 3091.3 g and a standard deviation of 704.9 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1500 g or a female who weighs 1500 g? ..... Since the z score for the male is z= and the z score for the female is z = the has the weight that is more extreme. (Round to two decimal places.)A survey found that women's heights are normally distributed with mean 63.4 in. and standard deviation 2.9 in. The survey also found that men's heights are normally distributed with mean 69.1 in. and standard deviation 3.4 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 56 in. and a maximum of 64 in. Complete parts (a) and (b) below. a. Find the percentage of men meeting the height requirement. What does the result suggest about the genders of the people who are employed as characters at the amusement park? The percentage of men who meet the height requirement is (Round to two decimal places as needed.) Since most men the height requirement, it is likely that most of the characters are b. If the height requirements are changed to exclude only the tallest 50% of men and the shortest 5% of men, what are the new height requirements? The new height requirements are a minimum of in. and a maximum of in. (Round to one decimal place as…
- Kennedy High School reported that the mean score on an end of semester physics exam wass 508 with a standard deviation of 121. Calculate the margin of error with a 95%confidence level for the data if the sample size was 200 students. A. 14.12% B. 17.95% C. 4.37% D. 16.77%In a random sample of 6 cell phones, the mean full retail price was $541.20 and the standard deviation was $183.00. Further research suggests that the population mean is $434.88. Does the t-value for the original sample fall between - to.99 and to.99? Assume that the population of full retail prices for cell phones is normally distributed. ... fall between - to.99 and to.99 because The t-value of t = to.99 = ₁ (Round to two decimal places as needed.)A survey found that women's heights are normally distributed with mean 63.9 in. and standard deviation 2.9 in. The survey also found that men's heights are normally distributed with mean 69.6 in. and standard deviation 3.3 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 56 in. and a maximum of 62 in. Complete parts (a) and (b) below. a. Find the percentage of men meeting the height requirement. What does the result suggest about the genders of the people who are employed as characters at the amusement park? The percentage of men who meet the height requirement is nothing%. (Round to two decimal places as needed.) Since most men ▼ the height requirement, it is likely that most of the characters are ▼ b. If the height requirements are changed to exclude only the tallest 50% of men and the shortest 5% of men, what are the new height requirements? The new height requirements are a minimum of…
- Students at a major university are complaining of a serious housing crunch. Many of the university’s student, they complain, have to commute too far to school because there is not enough housing near campus. The university officials respond with the following information: the mean distance commuted to school by students is 16.0 miles, and the standard deviation of the distance commuted is 3.0 miles. A) according to Chebyshev’s theorem, at least what percent of the commute distances lie between 10.0 miles and 22.0 miles. B) according to Chebyshev’s theorem, at least 8/9 (about 89%) of the commute distances lie between ? and ? Miles ?A survey found that women's heights are normally distributed with mean 62.9 in. and standard deviation 2.5 in. The survey also found that men's heights are normally distributed with mean 68.5 in. and standard deviation 3.7 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 57 in. and a maximum of 63 in. Complete parts (a) and (b) below. a. Find the percentage of men meeting the height requirement. What does the result suggest about the genders of the people who are employed as characters at the amusement park?Use z scores to compare the given values. Based on sample data, newborn males have weights with a mean of 3274.7 g and a standard deviation of 627.7 g. Newborn females have weights with a mean of 3038.5 g and a standard deviation of 683.3 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1700 g or a female who weighs 1700 g? Since the z score for the male is z = and the z score for the female is z = , the has the weight that is more extreme. (Round to two decimal places.)
