A sample of 0.425 mole NO with 0.626 mole Br2 in a 1.25 L reaction vessel gives an equilibrium mixture containing 0.113 mol NOBr. What is the composition of the equilibrium mixture in terms of Molarity?
A sample of 0.425 mole NO with 0.626 mole Br2 in a 1.25 L reaction vessel gives an equilibrium mixture containing 0.113 mol NOBr. What is the composition of the equilibrium mixture in terms of Molarity?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
- Nitrogen monoxide, NO, reacts with bromine, Br2, to give nitrosyl bromide, NOBr.
2??(?) + ??2(?) ⇄ 2????(?)
A sample of 0.425 mole NO with 0.626 mole Br2 in a 1.25 L reaction vessel gives an equilibrium mixture containing 0.113 mol NOBr. What is the composition of the equilibrium mixture in terms of Molarity?
Expert Solution
Step 1
Equilibrium is a condition at which the concentrations of different participating species becomes constant but both forward and backward reactions are proceeding at equal rates.
Step 2
The reaction involved is as shown below: 2NO + Br2 ⇄ 2NOBr
Initial moles of NO = 0.425 mol/1.25 L
= 0.340 M
Initial moles of Br2 = 0.626 mol/1.25 L
= 0.501 M
Assuming that 'x M' of the Br2 reacts till equilibrium, so, the ICE table is as shown below:
Molar concentration | [NO] | [Br2] | [NOBr] |
Initial | 0.340 | 0.501 | ----- |
Change | - 2x | - x | + 2x |
Equilibrium | 0.340 - 2x | 0.501 - x |
2x |
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