A sample of 0.425 mole NO with 0.626 mole Br2 in a 1.25 L reaction vessel gives an equilibrium mixture containing 0.113 mol NOBr. What is the composition of the equilibrium mixture in terms of Molarity?

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  1. Nitrogen monoxide, NO, reacts with bromine, Br2, to give nitrosyl bromide, NOBr.

 

2??(?)   +   ??2(?)    ⇄   2????(?)

 

A sample of 0.425 mole NO with 0.626 mole Br2 in a 1.25 L reaction vessel gives an equilibrium mixture containing 0.113 mol NOBr. What is the composition of the equilibrium mixture in terms of Molarity?

Expert Solution
Step 1

Equilibrium is a condition at which the concentrations of different participating species becomes constant but both forward and backward reactions are proceeding at equal rates.  

Step 2

The reaction involved is as shown below: 2NO + Br2 ⇄ 2NOBr

Initial moles of NO = 0.425 mol/1.25 L

= 0.340 M

Initial moles of Br2 = 0.626 mol/1.25 L

= 0.501 M

Assuming that 'x M' of the Br2 reacts till equilibrium, so, the ICE table is as shown below:

Molar concentration [NO]  [Br2] [NOBr]
Initial 0.340 0.501 -----
Change - 2x - x + 2x
Equilibrium 0.340 - 2x 0.501 - x

   2x

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