A sample mean, sample size, and population standard deviation are given. Uso ihe one-mean z-test to perform the required hypothesis test at the given significance level. Use the critical-value approach. x= 51, n= 46 , a= 3.6, Ho: u= 50; H > 50, a = 0.01

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### Hypothesis Testing Using One-Mean Z-Test

#### Problem Statement
A sample mean, sample size, and population standard deviation are given. Use the one-mean z-test to perform the required hypothesis test at the given significance level. Use the critical-value approach.

#### Given Data
- Sample mean (\( \overline{x} \)): 51
- Sample size (\( n \)): 46
- Population standard deviation (\( \sigma \)): 3.6
- Null hypothesis (\( H_0 \)): \( \mu = 50 \)
- Alternative hypothesis (\( H_a \)): \( \mu > 50 \)
- Significance level (\( \alpha \)): 0.01

#### Choices
1. \( z = 0.28 \); critical value = 2.33; do not reject \( H_0 \)
2. \( z = 1.884 \); critical value = 2.33; reject \( H_0 \)
3. \( z = 1.884 \); critical value = 1.33; reject \( H_0 \)
4. \( z = 1.884 \); critical value = 2.33; do not reject \( H_0 \)

#### Explanation:
1. **Choice A**:
   - \( z = 0.28 \)
   - Given the critical value of 2.33.
   - Since \( 0.28 < 2.33 \), we do not reject \( H_0 \).

2. **Choice B**:
   - \( z = 1.884 \)
   - Given the critical value of 2.33.
   - Since \( 1.884 < 2.33 \), we do not reject \( H_0 \).

3. **Choice C**:
   - \( z = 1.884 \)
   - Given the critical value of 1.33.
   - Since \( 1.884 > 1.33 \), we reject \( H_0 \).

4. **Choice D**:
   - \( z = 1.884 \)
   - Given the critical value of 2.33.
   - Since \( 1.884 < 2.33 \), we do not reject \( H_0 \).

#### Conclusion:
Based on the given choices, the correct conclusion is provided when \( z \)
Transcribed Image Text:### Hypothesis Testing Using One-Mean Z-Test #### Problem Statement A sample mean, sample size, and population standard deviation are given. Use the one-mean z-test to perform the required hypothesis test at the given significance level. Use the critical-value approach. #### Given Data - Sample mean (\( \overline{x} \)): 51 - Sample size (\( n \)): 46 - Population standard deviation (\( \sigma \)): 3.6 - Null hypothesis (\( H_0 \)): \( \mu = 50 \) - Alternative hypothesis (\( H_a \)): \( \mu > 50 \) - Significance level (\( \alpha \)): 0.01 #### Choices 1. \( z = 0.28 \); critical value = 2.33; do not reject \( H_0 \) 2. \( z = 1.884 \); critical value = 2.33; reject \( H_0 \) 3. \( z = 1.884 \); critical value = 1.33; reject \( H_0 \) 4. \( z = 1.884 \); critical value = 2.33; do not reject \( H_0 \) #### Explanation: 1. **Choice A**: - \( z = 0.28 \) - Given the critical value of 2.33. - Since \( 0.28 < 2.33 \), we do not reject \( H_0 \). 2. **Choice B**: - \( z = 1.884 \) - Given the critical value of 2.33. - Since \( 1.884 < 2.33 \), we do not reject \( H_0 \). 3. **Choice C**: - \( z = 1.884 \) - Given the critical value of 1.33. - Since \( 1.884 > 1.33 \), we reject \( H_0 \). 4. **Choice D**: - \( z = 1.884 \) - Given the critical value of 2.33. - Since \( 1.884 < 2.33 \), we do not reject \( H_0 \). #### Conclusion: Based on the given choices, the correct conclusion is provided when \( z \)
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