A sample consisting of 1 mol of He gas is initially at 240 kPa and 325 K. It undergoes reversible adiabatic expansion until its pressure reaches 150 kPa. Using equipartition theorem, find the ??,?, ??,? and ?. Calculate the final volume, final temperature and the work done? (Assume it is perfect gas)  ? = 5/3.

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A sample consisting of 1 mol of He gas is initially at 240 kPa and 325 K. It undergoes reversible
adiabatic expansion until its pressure reaches 150 kPa. Using equipartition theorem, find the ??,?,
??,? and ?. Calculate the final volume, final temperature and the work done? (Assume it is perfect
gas)  ? = 5/3.

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1+ Cvm/R.
Cy,m + R
Cy m
1+ c
1
- +1
Cp,m
Cy,m
C
C
The equation is now updated to:
Pi
= 1
The equation becomes:
P;V = p;V;"
This is reversible adiabatic expansion of perfect gas. For a monoatomic gas Cy m = 3/2 R and
Cpm = ½ R. So, the adiabatic exponent is y =
= 5/3.
A sample consisting of 1 mol of He gas is initially at 240 kPa and 325 K. It undergoes reversible
adiabatic expansion until its pressure reaches 150 kPa. Using equipartition theorem, find the Cy m,
C2m and y. Calculate the final volume, final temperature and the work done? (Assume it is perfect
gas)
8. One of the most fundamental output of the heat-work transactions in thermodynamics is
the Carnot CYcle, which is named after the French scientist Sadi Carnot. The cycle
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Transcribed Image Text:Midterm_2_Questions - Word Bengisu Sarıkaya File References Mailings Help Tell me what you want to do & Share Home Insert Draw Design Layout Review View 1+ Cvm/R. Cy,m + R Cy m 1+ c 1 - +1 Cp,m Cy,m C C The equation is now updated to: Pi = 1 The equation becomes: P;V = p;V;" This is reversible adiabatic expansion of perfect gas. For a monoatomic gas Cy m = 3/2 R and Cpm = ½ R. So, the adiabatic exponent is y = = 5/3. A sample consisting of 1 mol of He gas is initially at 240 kPa and 325 K. It undergoes reversible adiabatic expansion until its pressure reaches 150 kPa. Using equipartition theorem, find the Cy m, C2m and y. Calculate the final volume, final temperature and the work done? (Assume it is perfect gas) 8. One of the most fundamental output of the heat-work transactions in thermodynamics is the Carnot CYcle, which is named after the French scientist Sadi Carnot. The cycle Page 8 of 15 2630 words DE English (United States) %100
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