A sag vertical curve connects a -1.5 percent grade with a +2.5 percent grade on a rural arterial highway. If the criterion selected for design is the minimum stopping sight distance, and the design speed of the highway is 70 mi/h, compute the elevation of the curve at 100-ft stations if the grades intersect at station (475 +00) at an elevation of 300 ft. Use L = KA to find minimum curve length for this problem.

A sag vertical curve connects a -1.5 percent grade with a +2.5 percent grade on a rural arterial highway. If the criterion selected for design is the minimum stopping sight distance, and the design speed of the highway is 70 mi/h, compute the elevation of the curve at 100-ft stations if the grades intersect at station (475 +00) at an elevation of 300 ft. Use L = KA to find minimum curve length for this problem.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A horizontal curve in an urban area is being designed for 40 mph. If there is a maximum radius of…

Q: A highway must traverse a 6% followed by a -2% grade. The length of the crest vertical curve is 2040…

Q: Design a horizontal curve for the highway by computing the radius and stationing of PC and PT using…

A: Horizontal curve: A horizontal curve is a curve that provides the transition between two tangent…

Q: A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the…

Q: A sag vertical curve will connect a -1% grade to a 3% grade with a design speed of 50 mph. Using the…

Q: An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is −3% and…

Q: tangent vertical curve is intended to connect grades of 3.6% and -3.2%. If this curve is to be a…

Q: Determine the minimum length of a vertical curve between a -1.78% grade and a -7.8% grade for a road…

A: Answer we are given Grade G1 = -1.78% Grade G2 = -7.8% Design speed V = 110 Km/hr reaction time Rt…

Q: ical curve is going to be designed to join a 0% grade with a +5% grade at a section of a highway.…

A: as g1<g2curve is sag curve…

Q: 1. A crest vertical curve connects a +1.5 % grade with a -2.5 % grade on a two-lane highway. The…

A: Data given Grades = +1.5% and -2.5 % Design speed = 90 km/hr PI Station = 14+465 PI Elevation =…

Q: (TRAFFIC AND HIGHWAY ENGINEERING) A highway segment has an equal-tangent sag curve and a horizontal…

Q: Design a vertical curve connecting PVI₁ (station = 4+980, Elevation = 198 m), PVI₂ (station = 5+990,…

A: PVI₁ (station = 4+980, Elevation = 198 m) PVI₂ (station = 5+990, Elevation = 163 m) and PVI₃…

Q: A vertical curve is going to be designed to join a 0% grade with a +5% grade at a section of a…

A: G1 = 0% = 0 G2 = 5% = 0.05

Q: A crest vertical curve joining a + 3 percent and – 4 percent grade is to be designed for 75 mph. If…

Q: A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the…

Q: An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI…

Q: A vertical curve is needed to join to tangents; G1=0% and G2= -5%. Assuming a level grade (0%) for…

A: Vertical curves are formed when two different gradients meet at a point. If convexity of curve is…

Question

A sag vertical curve connects a -1.5 percent grade with a +2.5 percent grade on a
rural arterial highway. If the criterion selected for design is the minimum stopping
sight distance, and the design speed of the highway is 70 mi/h, compute the elevation
of the curve at 100-ft stations if the grades intersect at station (475 +00) at an
elevation of 300 ft. Use L = KA to find minimum curve length for this problem.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Final Answer:

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

only do question 4
An equal-tangent vertical curve is designed for the year 2030 for a design speed of 70 mi/h to connect grades G1 = 1.2% and G2 = - 2.1%. In 2030, vehicles have become smaller so that the driver's eye height is assumed to be 3.0 ft above the pavement and roadway objects are assumed to be 1.0 ft above the pavement surface. Compute the design curve length for the year 2030. A. 1178.02 В. 1032.09 C. 974.12 D. 980.25
An equal-tangent crest vertical curve is 1100 ft long and connects a +2.5% and a -1.5% grade. If the design speed of the roadway is 85 mi/h, determine the length of curve, does this curve have adequate passing sight distance?
An equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20
QUESTION 3 A vertical curve is needed to join to tangents; G₁-5% and G₂-2%. Assuming the worst case scenario for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 50 mph.
A+1 percent grade intersects with a-2 percent grade at station (535+ 24.25) at an elevation of 300 t. (a) if the design speed is 65 mi/h, determine the minimum length (in t) of vertical curve using the rate of vertical curvature. (Assume the stopping sight distance is less than the length of the curve.) it (b) Using the length found in part (a), find the stations and elevations (in R) of the BVC and EVC and the elevation (in t) of each 100 t station. (In the table below, the first row corresponds to the BVC and the last row corresponds to the EVC. Round your elevations to at least one decimal place.) Station Elevation (t) 533 + 00 534 + 00 535 + 00 536 + 00 537 + 00 538 + 00 (c) Using the length found in part (a), find the station and elevation (in t) of the highpoint. station nlevation
A vertical curve is needed to join to tangents; G1=1% and G2=4%. Assuming a level grade (0%) for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 60 mph.
A section of a two-lane highway (one lane in each direction) (12-ft lanes) is designed for 55 mi/h. At one point a vertical curve connects a -2.9% and +1.8% grade. The PVT of this curve is at station 38 + 50. It is known that a horizontal curve starts (has PC) 247 ft before the vertical curve's PVC. If the superelevation of the horizontal curve is 0.08 and the central angle is 39 degrees, what is the station of the PT (express station in the format 0.00, for example, station 10+50 must be expressed as 10.5)?
A circular curve of the highway is designed for traffic moving at 50 mi/hr. If the radius of the curve is 550 ft, what is the correct angle of banking of the road?