A runner of mass 50.1 kg starts from rest and accelerates with a constant acceleration of 1.1 m/s2 until she reaches a velocity of 6.5 m/s. She then continues running at this constant velocity. How long in seconds does the runner take to travel 104 m?

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A runner of mass 50.1 kg stařts from rest and accelerates with a constant acceleration
of 1.1 m/s2 until she reaches a velocity of 6.5 m/s. She then continues running at this
constant velocity. How long in seconds does the runner take to travel 104 m?
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Transcribed Image Text:A runner of mass 50.1 kg stařts from rest and accelerates with a constant acceleration of 1.1 m/s2 until she reaches a velocity of 6.5 m/s. She then continues running at this constant velocity. How long in seconds does the runner take to travel 104 m? 载
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Step 1

The given runner has a mass of 50.1 kg, and they begin their run starting from rest, and runs with a constant acceleration of 1.1 m/s2.

This acceleration is maintained at a constant value, until the runner reaches a velocity of 6.5 m/s, and after reaching this velocity they maintain this at a constant. Thus this means after this mark the acceleration of the runner is zero.

The runner begins from rest, so the initial velocity is zero. A constant acceleration of 1.1 m/s2 is maintained until a final velocity of 6.5 m/s is acheived.

Using kinematical equations of motion,

v=u+atv is the final velocity at time tu is the initial velocitya is the acceleration

So the time taken to reach 6.5 m/s is 

6.5=0+1.1×t1.1t=6.5t=6.51.1t=5.909 s

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