A rough rule of thumb in polymer solution theory is that a 4 molar aqueous polymer solution will have an osmotic pressure of approximately 100 bar. Is this rule of RT In (x water) ? A 4 thumb in approximate agreement with the expression t=- Vwater molar solution is 4 moles per liter of solution, which approximately contains 55 moles of water. First, show that the mole fraction of water xwater Will be 0.9322. Then use R = 8.314x10-5 bar-m³/mol-K, T = 298.15 K, Vwater = 18.015x10-6 m/mol for the remainder of your calculation.
A rough rule of thumb in polymer solution theory is that a 4 molar aqueous polymer solution will have an osmotic pressure of approximately 100 bar. Is this rule of RT In (x water) ? A 4 thumb in approximate agreement with the expression t=- Vwater molar solution is 4 moles per liter of solution, which approximately contains 55 moles of water. First, show that the mole fraction of water xwater Will be 0.9322. Then use R = 8.314x10-5 bar-m³/mol-K, T = 298.15 K, Vwater = 18.015x10-6 m/mol for the remainder of your calculation.
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![A rough rule of thumb in polymer solution theory is that a 4 molar aqueous polymer
solution will have an osmotic pressure of approximately 100 bar. Is this rule of
RT In(xwater)? A 4
thumb in approximate agreement with the expression t=-
V water
molar solution is 4 moles per liter of solution, which approximately contains 55 moles
of water. First, show that the mole fraction of water xwater Will be 0.9322. Then use R =
8.314x10-5 bar-m³/mol-K, T = 298.15 K, Vwater = 18.015×10-6 m/mol for the
remainder of your calculation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F043dff29-6684-46d5-915e-65013d4ca58c%2F1348cbf3-f102-43d1-bf81-6ee90d7e57a6%2Fi6ai6t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A rough rule of thumb in polymer solution theory is that a 4 molar aqueous polymer
solution will have an osmotic pressure of approximately 100 bar. Is this rule of
RT In(xwater)? A 4
thumb in approximate agreement with the expression t=-
V water
molar solution is 4 moles per liter of solution, which approximately contains 55 moles
of water. First, show that the mole fraction of water xwater Will be 0.9322. Then use R =
8.314x10-5 bar-m³/mol-K, T = 298.15 K, Vwater = 18.015×10-6 m/mol for the
remainder of your calculation.
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