A rotation rate, or frequency, of 500 nHz corresponds to a rotation period of 23 days—it takes 23 days for material to follow one complete circle around the Sun. Furthermore, the frequency and period are inversely proportional to one another: if one is doubled, the other is halved. Given these facts, what is the approximate rotation period (in days) for equatorial material at the Sun's surface? (Use your answer to the previous question as the rotation rate.)
A rotation rate, or frequency, of 500 nHz corresponds to a rotation period of 23 days—it takes 23 days for material to follow one complete circle around the Sun. Furthermore, the frequency and period are inversely proportional to one another: if one is doubled, the other is halved. Given these facts, what is the approximate rotation period (in days) for equatorial material at the Sun's surface? (Use your answer to the previous question as the rotation rate.)
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A rotation rate, or frequency, of 500 nHz corresponds to a rotation period of 23 days—it takes 23 days for material to follow one complete circle around the Sun. Furthermore, the frequency and period are inversely proportional to one another: if one is doubled, the other is halved. Given these facts, what is the approximate rotation period (in days) for equatorial material at the Sun's surface? (Use your answer to the previous question as the rotation rate.)
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