A rotating wheel requires 5.00 s to rotate 30.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 99.0 rad/s. What is the constant angular acceleration (in rad/s) of the wheel? Use the kinematic equation for angular displacement in terms of angular velocity and angular acceleration to solve for the angular acceleration required for the wheel to rotate as described in the question. rad/s? Need Help? Master It Read It

A rotating wheel requires 5.00 s to rotate 30.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 99.0 rad/s. What is the constant angular acceleration (in rad/s) of the wheel? Use the kinematic equation for angular displacement in terms of angular velocity and angular acceleration to solve for the angular acceleration required for the wheel to rotate as described in the question. rad/s? Need Help? Master It Read It

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The 50 mm radius pulley A of the clothes dryer rotates with an angular acceleration of or= (2582) rad/s². where is in radians. (Figure 1) Figure 50 mm 1 of 1 Part A Determine its angular acceleration when f = 2 s. starting from rest Express your answer to three significant figures and include the appropriate Inits. 122.4 Submit HÅ Provide Feedback rad s² Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
The rotating blade of a blender turns with a constant angular acceleration 1.50(rad/s²]. A. How much time does it take to reach an angular velocity of 36. 0 [rad/s] starting from rest? Through how manry revolutions does the blade turn in this time interval? C. What are the tangertial acceleration and tangential speed of an ant sitting on the blade 10.0 [cm) from the axis of rotation during the end of this irterval? D. What is the moment of inertia ofthe ant if its mass is 10.0 (g? E. What is the rotational kinetic energy of the ant? B.
A child with mass 42 kg sits on the edge of a merry-go-round at a distance of 3.0 m from its axis of rotation. The merry-go-round accelerates from rest up to 0.40 rev/s in 10 s. a. What is the angular acceleration of the merry-go-round? Express this in radians/second. b. What is the angular velocity at 5 s? c. Calculate the centripetal acceleration and tangential acceleration at 5 s. d. What is the total acceleration at 5 s? e. If the coefficient of static friction between the child and the surface of the merry-go-round is 0.6, does the child fall off before 5 s? Hint: To determine this, calculate the frictional force and force due to the acceleration of the merry-go-round on the child. Compare the two forces to find which is larger than the other, therefore overcomes the other.
pls help
Cyclist! A cyclist starts from rest and pedals such that the wheels of his bike have a constant angular acceleration. After 14 s, the wheels have made 48 rev. What is the angular velocity of the wheels after 14 s in rad/s ? rad/s Submit Answer Tries 0/2 What is the angular acceleration of the wheels in rad/s² ? rad/s² Submit Answer Tries 0/2 If the radius of the wheel is 37 cm, and the wheel rolls without slipping, how far has the cyclist (in m) traveled in 14 s? m Submit Answer Tries 0/2
A solid cylinder of radius 13.0 cm rolls down an incline with slipping. The angle of the incline is 25°. The coefficient of kinetic friction on the surface is 0.451. What is the angular acceleration (in rad/s2) of the solid cylinder? (Enter the magnitude.) rad/s² What is the linear acceleration (in m/s2)? (Assume v> ar. Enter the magnitude.) m/s²
A rotating wheel requires 5.00 s to rotate 29.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 rad/s. What is the constant angular acceleration (in rad/s) of the wheel? rad/s2
A rotating wheel requires 3.08-s to rotate through 37.0 revolutions. Its angular speed at the end of the 3.08-s interval is 98.3 rad/s. What is the constant angular acceleration of the wheel? rad/s2
During a very quick stop, a car deceleraes at 7.00 m/s^2.a. What is the angular acceleration of its 0.280-m-radius tires, assuming they do not slip on the pavement?b. How many revolutions do the tires make before coming to rest, given their initial angular velocity is 95.0 rad/s?c. How long does the car take to stop completely?d. What distance does the car travel in this time?e. What was the car’s initial velocity?f. Do the values obtained seem reasonable, considering that this stop happens very quickly?
A dentist's drill starts from rest. After 3.40 s of constant angular acceleration it turns at a rate of 2.30 x 10 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad
A rotating wheel requires 3.0 seconds to rotate through 233.0 radians. Its angular speed at the end of the 3.0-second interval is 98.0 rad/s. Find: a. The angular speed at the beginning of the 3.0-second interval. b. The constant angular acceleration of the wheel.
A rotating wheel requires 6.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 6.00-s interval is 95.0 rad/s. What is the constant angular acceleration (in rad/s) of the wheel? rad/s2