A robot is deployed on Mars to study the presence of organic material. It is estimated that its lifespan T will follow the probabilistic law P(T > t) = e-/3. This equation can be interpreted as saying that the probability that the robot will work at least T years is a decaying exponential. For instance, the probability that the robot will last one year or more is P(T > 1) = e¬1/3 = 0.72 The robot is deployed, and after three years it is still working. What is the probability that it will break at the end of the fourth year?

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A robot is deployed on Mars to study the presence of organic material. It is estimated that its lifespan
T will follow the probabilistic law
P(T > t) = e-/3.
This equation can be interpreted as saying that the probability that the robot will work at least T
years is a decaying exponential. For instance, the probability that the robot will last one year or
more is
P(T > 1) = e¬1/3 = 0.72
The robot is deployed, and after three years it is still working. What is the probability that it will
break at the end of the fourth year?
Transcribed Image Text:A robot is deployed on Mars to study the presence of organic material. It is estimated that its lifespan T will follow the probabilistic law P(T > t) = e-/3. This equation can be interpreted as saying that the probability that the robot will work at least T years is a decaying exponential. For instance, the probability that the robot will last one year or more is P(T > 1) = e¬1/3 = 0.72 The robot is deployed, and after three years it is still working. What is the probability that it will break at the end of the fourth year?
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