A river has a steady speed of vg. A student swims upstream a distance d and back to the starting point. (a) If the student can swim at a speed of v in still water, how much time t.n does it take the student to swim upstream a distance d? Express your answer in terms of d, v, and v tup = v+ v (b) Using the same variables, how much time tdown does it takes to swim back downstream to the starting point? d tdown = v+vs

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Topic: Swimming Against and With the Current**

A river has a steady speed of \( v_s \). A student swims upstream a distance \( d \) and back to the starting point.

**Problem a: Time to Swim Upstream**

If the student can swim at a speed of \( v \) in still water, how much time \( t_{\text{up}} \) does it take for the student to swim upstream a distance \( d \)? Express your answer in terms of \( d \), \( v \), and \( v_s \).

\[ t_{\text{up}} = \frac{d}{v - v_s} \]

*Note: There is an error indicated with an "x" next to the equation.*

**Problem b: Time to Swim Downstream**

Using the same variables, how much time \( t_{\text{down}} \) does it take to swim back downstream to the starting point?

\[ t_{\text{down}} = \frac{d}{v + v_s} \]

*Note: There is an error indicated with an "x" next to the equation.*

**Description:**

The image explains a scenario where a student swims in a river with a current. There are two parts: calculating the time to swim upstream against the current and downstream with the current. Equations for both parts are given, but both have a red "x" indicating a mistake. This might be a hint to review and correct or analyze what is incorrect.
Transcribed Image Text:**Topic: Swimming Against and With the Current** A river has a steady speed of \( v_s \). A student swims upstream a distance \( d \) and back to the starting point. **Problem a: Time to Swim Upstream** If the student can swim at a speed of \( v \) in still water, how much time \( t_{\text{up}} \) does it take for the student to swim upstream a distance \( d \)? Express your answer in terms of \( d \), \( v \), and \( v_s \). \[ t_{\text{up}} = \frac{d}{v - v_s} \] *Note: There is an error indicated with an "x" next to the equation.* **Problem b: Time to Swim Downstream** Using the same variables, how much time \( t_{\text{down}} \) does it take to swim back downstream to the starting point? \[ t_{\text{down}} = \frac{d}{v + v_s} \] *Note: There is an error indicated with an "x" next to the equation.* **Description:** The image explains a scenario where a student swims in a river with a current. There are two parts: calculating the time to swim upstream against the current and downstream with the current. Equations for both parts are given, but both have a red "x" indicating a mistake. This might be a hint to review and correct or analyze what is incorrect.
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