A ring of mass 0.2 kg is placed at the top of an inclined plane with angle 0 = 30°. The ring has radius 10 cm and rolls from rest without slipping. Given that the rotational inertia of a ring is MR², calculate Ring R= 10 cm M= 0.2 kg e = 30° (a) the magnitude of friction between the ring and plane. (b) the magnitude of torque applied on the ring. (c) the magnitude of angular acceleration of the ring. (d) the magnitude of angular momentum after 2 s. (e) the kinetic energy after 2 s.
A ring of mass 0.2 kg is placed at the top of an inclined plane with angle 0 = 30°. The ring has radius 10 cm and rolls from rest without slipping. Given that the rotational inertia of a ring is MR², calculate Ring R= 10 cm M= 0.2 kg e = 30° (a) the magnitude of friction between the ring and plane. (b) the magnitude of torque applied on the ring. (c) the magnitude of angular acceleration of the ring. (d) the magnitude of angular momentum after 2 s. (e) the kinetic energy after 2 s.
Related questions
Question
Transcribed Image Text:A ring of mass 0.2 kg is placed at the top of an inclined plane with angle 0 = 30°. The ring has
radius 10 cm and rolls from rest without slipping. Given that the rotational inertia of a ring is
MR?, calculate
Ring
R = 10 cm
M = 0.2 kg
0 = 30°
(a) the magnitude of friction between the ring and plane.
(b) the magnitude of torque applied on the ring.
(c) the magnitude of angular acceleration of the ring.
(d) the magnitude of angular momentum after 2 s.
(e) the kinetic energy after 2 s.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 4 steps with 4 images
