SERPSE10 18.5.OP.018.A rigid tank contains an amount of oxygen at a pressure of 11.2 atm and a temperature of 29.0°C. Two-thirds of the gas is withdrawn from the tank, while the temperature of the remainder is raised to 87.0°C. What is the new pressure (in atm) of the gas remaining in thetank?DETAILSSubmit AnsweratmView Previous Question Question 10 of 19 View Next QuestionASK YOUR TEACHER

We will answer the question using the ideal gas law. The details are given below.For a gas in a container, the ideal gas law is given by PV=nRT Here, P is the pressure of the gas in units of N/m2 or Pa V is the volume occupied by gas(that is, volume of container) in units of m3 n is the number of moles of gas R is the universal gas constant T is the temperature of the gas in units of K In the beginning, the pressure of oxygen is P=11.2 atm=11.2×1.01×105 Pa=11.3×105 Pa and temperature is T=29°C=29+273K=302 K and volume of rigid tank is V. Using these values in the above equation, we get 11.3×105×V=nR×302 .......(1) Afterwards, we are given that two-thirds of the gas is drawn from the tank. So now only one third of the original amount of gas remains in the tank. That is, out of the original 'n' moles of gas, we now have 13n moles of gas. Also the temperature now is T=87°C=87+273 K=360 K. Volume of the rigid tank is unchanged and is still V. Let the unknown pressure be P. Using these values in the ideal gas law, we get P×V=13nR×360 .......(2) Now, dividing equation (2) by equation (1) we get P×V11.3×105×V=13nR×360 nR×302 P=11.3×105×3603×302 Cancelling common terms in numerator and denominatorP=4.49×105 PaP=4.49×105 1.01×105 atmP=4.44 atm Therefore, new pressure of the gas remaining in tank is 4.44 atm

Answered: A rigid tank contains an amount of…

A rigid tank contains an amount of oxygen at a pressure of 11.2 atm and a temperature of 29.0°C. Two-thirds of the gas tank? atm withdrawn from t perature of the remainder is raised to 87.0°C. What is the new pressure (in atm) of the gas remaining in the