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A rigid (constant volume) balloon is inflated at sea level, then submerged underwater, doubling the pressure on the gas. Explain how the temperature changes. A mixture of saturated water has quality x = 0.75 at temperature 90°C. Determine the average specific volume, v.

A rigid (constant volume) balloon is inflated at sea level, then submerged underwater, doubling the pressure on the gas. Explain how the temperature changes. A mixture of saturated water has quality x = 0.75 at temperature 90°C. Determine the average specific volume, v.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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(Practice Only) A rigid (constant volume) balloon is inflated at sea level, then submerged underwater, doubling the pressure on the gas. Explain how the temperature changes. A mixture of saturated water has quality x = 0.75 at temperature 90°C. Determine the average specific volume, v. For water at 60°C and 500 kPa, determine the internal energy, u, quality, x, and phase description. Explain how answer.
Transcribed Image Text:(Practice Only) A rigid (constant volume) balloon is inflated at sea level, then submerged underwater, doubling the pressure on the gas. Explain how the temperature changes. A mixture of saturated water has quality x = 0.75 at temperature 90°C. Determine the average specific volume, v. For water at 60°C and 500 kPa, determine the internal energy, u, quality, x, and phase description. Explain how answer.
Expert Solution
Step 1

A rigid balloon is inflated and submerged underwater and the pressure is doubled. From the gas constant,

PV = mRT

Since the volume is constant and the pressure is doubled and hence the temperature will also be doubled.

 

 

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