A right triangular lamina of uniform density oriented in the x-y plane as shown. a A uniform density disk of radius R with a circular cut-out of radius R/2.
A right triangular lamina of uniform density oriented in the x-y plane as shown. a A uniform density disk of radius R with a circular cut-out of radius R/2.
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What’s the center of mass for each situation?

Transcribed Image Text:**Right Triangular Lamina:**
The first diagram illustrates a right triangular lamina with uniform density. This triangle is oriented in the x-y plane, with the right angle positioned at the origin (0,0). The triangle's sides are aligned with the coordinate axes: one side extends along the x-axis to a length "a" while the other extends along the y-axis to a length "a." This setup is essential for calculations involving moments of inertia or center of mass.
**Uniform Density Disk:**
The second diagram shows a uniform density disk with an overall radius "R." However, this disk has a smaller circular cut-out with a radius of "R/2" removed from its center. The disk's center coincides with the center of the cut-out. This configuration is significant in studying topics like mass distribution and rotational dynamics, as it provides practical examples of composite shapes and density variations.
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