A right triangle has side lengths 5, 12, and 13 as shown below. Use these lengths to find cos.A, tanA, and sin.A. 12 13

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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A right triangle has side lengths 5, 12, and 13 as shown below. Use these lengths to find cos A, tan A, and sin A.

The diagram shows a right triangle with:
- Hypotenuse \( AB = 13 \)
- Opposite side \( AC = 12 \)
- Adjacent side \( BC = 5 \)

Based on the right triangle:
- \( \cos A = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{5}{13} \)
- \( \tan A = \frac{\text{opposite}}{\text{adjacent}} = \frac{12}{5} \)
- \( \sin A = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{12}{13} \)

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Transcribed Image Text:A right triangle has side lengths 5, 12, and 13 as shown below. Use these lengths to find cos A, tan A, and sin A. The diagram shows a right triangle with: - Hypotenuse \( AB = 13 \) - Opposite side \( AC = 12 \) - Adjacent side \( BC = 5 \) Based on the right triangle: - \( \cos A = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{5}{13} \) - \( \tan A = \frac{\text{opposite}}{\text{adjacent}} = \frac{12}{5} \) - \( \sin A = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{12}{13} \) [There is a placeholder for entering values, with a reset and help option beside it.]
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