A reversible refrigeration cycle offers a cooling capacity equal to Q₁ = 20 kJ/s while 5 kW of power are supplied to the compressor, see figure below. The temperature of the cooled space is -13°C and the ambient around the refrigerator has a temperature equal to 27°C (i.e., the kitchen). Please answer the following. TH Он 3 --- Expansion valve Condenser Evaporator Compressor 2 Win T₁ a. Compute the heat transfer rate from the refrigeration cycle to the surroundings. b. Determine the COP of the refrigerator based on the energy rates information given to you. c. Suddenly you start questioning whether this refrigerator can operate as described to you. So, you decide to investigate the feasibility of the cycle and remember that according to the First Carnot Principle, for a heat engine, the maximum thermal efficiency is that of a reversible cycle, such as a Carnot Cycle. Since you know that the Carnot Cycle is reversible you conceptualize a cycle like the reversed Carnot Cycle for which the maximum COP is obtained. For your own peace of mind, you decide to sketch a process diagram for a reversed Carnot cycle that operates between T₁ = -13°C and T = 27°C. In this part you are asked to sketch the cycle on a P-v diagram, include the values for the temperatures in the isotherms and include in the specific volume axis the corresponding symbols for V1, V2, V3 and V4. d. For your reversed Carnot cycle, compute the COP. e. Now that you have a value for the maximum possible COP for a refrigeration cycle operating between the given temperatures T₁ and Tн you can determine whether the heat transfer rates for the refrigeration cycle indeed are true. So, was your concern in part (c) valid or you were sweating the small stuff (note, in thermodynamics there is no small stuff)?
A reversible refrigeration cycle offers a cooling capacity equal to Q₁ = 20 kJ/s while 5 kW of power are supplied to the compressor, see figure below. The temperature of the cooled space is -13°C and the ambient around the refrigerator has a temperature equal to 27°C (i.e., the kitchen). Please answer the following. TH Он 3 --- Expansion valve Condenser Evaporator Compressor 2 Win T₁ a. Compute the heat transfer rate from the refrigeration cycle to the surroundings. b. Determine the COP of the refrigerator based on the energy rates information given to you. c. Suddenly you start questioning whether this refrigerator can operate as described to you. So, you decide to investigate the feasibility of the cycle and remember that according to the First Carnot Principle, for a heat engine, the maximum thermal efficiency is that of a reversible cycle, such as a Carnot Cycle. Since you know that the Carnot Cycle is reversible you conceptualize a cycle like the reversed Carnot Cycle for which the maximum COP is obtained. For your own peace of mind, you decide to sketch a process diagram for a reversed Carnot cycle that operates between T₁ = -13°C and T = 27°C. In this part you are asked to sketch the cycle on a P-v diagram, include the values for the temperatures in the isotherms and include in the specific volume axis the corresponding symbols for V1, V2, V3 and V4. d. For your reversed Carnot cycle, compute the COP. e. Now that you have a value for the maximum possible COP for a refrigeration cycle operating between the given temperatures T₁ and Tн you can determine whether the heat transfer rates for the refrigeration cycle indeed are true. So, was your concern in part (c) valid or you were sweating the small stuff (note, in thermodynamics there is no small stuff)?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Hi, can you only help with A and B here? I am looking to get this started. Please draw a clear schematic if you think it differs from the picture in any respect.
Transcribed Image Text:A reversible refrigeration cycle offers a cooling capacity equal to Q₁ = 20 kJ/s while 5 kW of power are
supplied to the compressor, see figure below. The temperature of the cooled space is -13°C and the
ambient around the refrigerator has a temperature equal to 27°C (i.e., the kitchen). Please answer the
following.
TH
Он
3
---
Expansion
valve
Condenser
Evaporator
Compressor
2
Win
T₁
a. Compute the heat transfer rate from the refrigeration cycle to the surroundings.
b. Determine the COP of the refrigerator based on the energy rates information given to you.
c. Suddenly you start questioning whether this refrigerator can operate as described to you. So,
you decide to investigate the feasibility of the cycle and remember that according to the First
Carnot Principle, for a heat engine, the maximum thermal efficiency is that of a reversible
cycle, such as a Carnot Cycle. Since you know that the Carnot Cycle is reversible you
conceptualize a cycle like the reversed Carnot Cycle for which the maximum COP is
obtained. For your own peace of mind, you decide to sketch a process diagram for a reversed
Carnot cycle that operates between T₁ = -13°C and T = 27°C. In this part you are asked to
sketch the cycle on a P-v diagram, include the values for the temperatures in the isotherms
and include in the specific volume axis the corresponding symbols for V1, V2, V3 and V4.
d. For your reversed Carnot cycle, compute the COP.
e.
Now that you have a value for the maximum possible COP for a refrigeration cycle operating
between the given temperatures T₁ and Tн you can determine whether the heat transfer rates
for the refrigeration cycle indeed are true. So, was your concern in part (c) valid or you were
sweating the small stuff (note, in thermodynamics there is no small stuff)?
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