A reversed curve of unequal radii has R2 = 1500 ft. The parallel distance between the tangents is 150 ft and the second curve have a central angle of 18°. PT is at 12+98. Find the following: Length of the long chord Radius of the first curve Stationing of PC Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.
A reversed curve of unequal radii has R2 = 1500 ft. The parallel distance between the tangents is 150 ft and the second curve have a central angle of 18°. PT is at 12+98. Find the following: Length of the long chord Radius of the first curve Stationing of PC Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
A reversed curve of unequal radii has R2 = 1500 ft. The parallel distance between the tangents is 150 ft and the second curve have a central angle of 18°. PT is at 12+98.
Find the following:
- Length of the long chord
- Radius of the first curve
- Stationing of PC
Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.

Transcribed Image Text:PC
T1
V1
Le1
T1
R2
Iz
R1
R2
T2
R1
Lcz
I1
PRC
V2
T2
Common tangent
PT
Reversed Curves
PC
V1
back tangent
R2
forward tangent
PRC
PT
I2
V2
R1
R1
Reversed Curves for Nonparallel Tangents
PC
V1
back tangent
R2
R2
PRC
forward tangent
V2
PT
R1
I
R1
Reversed Curves for Parallel Tangents
Elements of Reversed Curve
• PC = point of curvature
%3D
• PT = point of tangency
• PRC = point of reversed curvature
T1 = length of tangent of the first curve
T2 = length of tangent of the second curve
%3D
V1
= vertex of the first curve
V2 = vertex of the second curve
• I1 = central angle of the first curve
I2 = central angle of the second curve
Lc1 = length of first curve
Lc2 = length of second curve
L1 = length of first chord
%D
L2 = length of second chord
T1 + T2 = length of common tangent
measured from Vị to V2
%3D
Finding the stationing of PT
Given the stationing of PC
Sta PT = Sta PC + Le1 + L2
|
Given the stationing of V1
Sta PT = Sta Vị – Tị + Lcl + Le2
-
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