A reverse curve of equal radii connects 2 parallel tangents 21 m apart. The length of the chord from PC to PT is 140m. PC is at 3+100 1. Determine the Intersection angle    a) 12.57    b) 15.72    c) 17.25    d) 71.52 2. Determine the radius of the curve    a) 333.22    b) 222.33    c) 233.33    d) 322.22

Q: SITUATION 5: A compound curve has the following data: Li = 28° DI = 3° D2 = 4° L2 = 31° Sta. P.I at…

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Q: The offset distance of the simple curve from the P.T. to tangent line passing through P.C. is equal…

A: sin50=120.2PI-PTT=RtanI2156.91=Rtan502R=336.49mD=1781.9336.49=5

Q: Station PT of a compound curve is at 15+480, 11=30°, 12=36°, D1=4°, and D2=5°. is the stationing…

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Q: A horizontal curve is designed with a '500' m radius. The curve has a tangent length of 120 m and…

A: Radius of curve = 500 mTangent length = 120 mStationing of PI = 3 + 140 mDeflection angle  = ◇(…

Q: 1. The intersection of two proposed tangent AB and CD are inaccessible. Therefore, from point E…

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Q: The station of the Pl of a horizontal curve is 60+20. The horizontal curve will have a curve degree…

A: Given,PI = 60 + 20Degree of curve, D = 4oLength, L = 400 ft

Q: Two roads AB and BC intersect at a chainage 184+65. These are intersected by a line PQ and the…

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Q: Two roads AB and BC intersect at a chainage 184+65. These are intersected by a line PQ and the…

A: GIVEN :- Radius of the curve  R1 = 330 m R2 = 540 m To Determine :- chainages of the first and the…

Q: Problem 7. 7.Station PT of the compound curve is at 15 + 480.14. I, = 30°, I2 = 36°, D1 = 4°, D2 =…

A: We know that ; D=1145.92R Can be written as  ; R2 = 1145.92D2 R2 = 1145.925 = 229.184 m

Q: nd BC with bearings 58deg 30' E respec e vertex is 4+360.2

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Q: Two tangents intersect at sta. +550. A compound curved laid on their tangents has the following…

A: Given Data:Tangents intersection=0+550I1=31°;I2=36°,D1=3°,D2=5° It is required to compute stationing…

Q: Simple Curves: A highway curve was designed to connect intersecting tangents at Pl. Back tangent = N…

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Q: Determine the common tangent of a reversed curve given the following prop 11 = 15.26° D₁ = 4.98° 12…

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Q: A compound circular curve has: R₁ = 500m, R₂ = 750m, A₁ = 38° 20', A2 = 41° 30′ St. P.I = (28+50)…

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Q: B R

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Q: a. Elements of the curve b. Stationing of P.C. and P.T. c. Lengths of sub-chords and its…

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Q: A COMPOUND CURVE is composed of three simple curves (CURVE1, CURVE2 & CURVE3). Compute the…

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Q: 2. The tangent lines of a simple curve have azimuths 300 and bearing N 04 E, respectively. A third…

A: tangent lines of simple curve have azimuths 3000 abd bearing N040EAB intersects the two tangent…

Q: the bearing of line AB is N 75° E, and the azimuth of line BC from north meridian is 98°. If the…

A: Given that bearing of line AB is N 75° E

Q: the horizontal distance from the center of long chord is 2.75 m, what is the offset distance from…

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Q: Four simple curves (CURVE1, CURVE2 & CURVE3) are connected to form the highway curves. CURVE2 formed…

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Q: Four simple curves (CURVE 1 CURVE 2 CURVE 3 are connected to form the highway curves CURVE 2 formed…

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Q: A compound horizontal curve is provided in the figure below. I1 = 72°00'". I2 = 58°00'. BC station…

A: A compound curve is given, with different radii R1 =500 ft and R2 = 750 ft The stationing of the…

Q: 1. 1. A simple curve connects two tangents AB and BC with bearings N 85 deg 30' E and S68deg 30' E…

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Q: A vertical sag parabolic curve has a length of 450m. Its back tangent has a slope of -3.20%. The…

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Q: PI = Sta 1+395.43 1 = 43° 39' Arc basis, D = 4° 15'

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Q: Situation 1: A simple curve have tangents AB and BC intersecting at a common point B. AB has an…

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Q: A simple curve connects two tangents AB and BC with bearing N 85°30' E and S 68°30' E, respectively.…

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Q: Two Straight lines AB and BC intersect at chainage 7827 m, the deflection angle being (49)ᴼ . It is…

A: As we know formula of design of curve Let us take 30m Chain length R= 1720/D°    = 1720/4°  R  =…

Q: Given the following elements of the compound curve shown: h = 37° 30' I2 = 53° 50' R1 = 250 m. %3D…

A: T1=215m

Q: nects two tangents AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E respectively. If…

A: Given:- AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E stationing of the Vertex is…

Q: Curves Problem: 1+12 For the given compound curve (see figure): a. Determine R, and R2. b. Determine…

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Q: The PI of a highway is located in a lake at point C. Stations A and B are selected to replace the…

A: Note:- Hi! Thank you for the question, As per the honor code, we are allowed to answer three…

Q: The backward tangent of +5% and a forward tangent of -3% is connected by a vertical symmetrical…

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Q: The bearings of forward and backward tangent are N 15°30’ E and N 25°40’ W, respectively. If the…

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Q: Given a compound curve 1=24 deg, 12=36 deg, D1=6 deg, D2=4 deg., Stationing PC is at 6+029.21. a.…

A: Given data- For the compound curve-I1=24oD1=6oAlso,I2=36oD2=4oTo Find-(a) Length of the common…

Q: A simple curve connects two tangent AB and BC with bearing N 85°30' E and S 68°30' E respectively.…

A: Consider the free body diagram;

Q: The tangents of a simple curve have bearings of N 65°12' E and S39°56' E, respectively. | is the…

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Q: Station PT of a compound curve is at 15+ 480, I, = 30°,I2 = 36°, D1 = 4°, and D2 = 5°. What is the…

A: To Find Station of P.C.C Given I1 = 30° I2 = 36° D1 = 4° D2 = 5° PT station = 15+480

Coordinate Geometry of Survey

Coordinate geometry (COGO) is a method of inserting surveying or engineering data into geographic information system (GIS), computer-aided design (CAD), or mapping software. These data can be collected on the proposed construction site using standard surveying techniques and instrumentation or may be taken from existing maps, engineering plans, drawings, or records. Data gathered on the site includes coordinates of points, bearings, and distances between points. The data are noticed and noted through conventional surveying procedures, like a traverse or layout measurement series and it can be either digital or non-digital. The maps and plans are inclusive of boundaries, divisions, and other components, and these features are shown with coordinate values, the lengths, offset distance, and bearings between them.