(a) Resistors of 20N, 202 and 302 are connected in parallel. What resistance must be add series with the combination to obtain a total resistance of 102. b) For the circuit shown, calculate (i) the equivalent resistance

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(a) Resistors of 202, 202 and 302 are connected in parallel. What resistance must be added in
series with the combination to obtain a total resistance of 102.
(b) For the circuit shown, calculate
(i) the equivalent resistance
(ii) the current through 42 resistor
(iii) the power delivered to 32 resistor.
R1
12.0 V = V
R4
8.00 N
R2
3.00 2
R3
4.00 N
1.00 N
Transcribed Image Text:(a) Resistors of 202, 202 and 302 are connected in parallel. What resistance must be added in series with the combination to obtain a total resistance of 102. (b) For the circuit shown, calculate (i) the equivalent resistance (ii) the current through 42 resistor (iii) the power delivered to 32 resistor. R1 12.0 V = V R4 8.00 N R2 3.00 2 R3 4.00 N 1.00 N
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