A resistor is connected across the terminals of a 9.0-V battery, which delivers 1.0 x 105 J of energy to the resistor in 6.0 hours. What isthe resistance of the resistor?Number iUnits

Given, Voltage of the battery V=9 V Energy E=1×105 J time t=6 h=(6×3600)=21600 s We know, Energy…

Answered: A resistor is connected across the…

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A resistor is connected across the terminals of a 9.0-V battery, which delivers 1.0 x 105 J of energy to the resistor in 6.0 hours. What is
the resistance of the resistor?
Number i
Units

Expert Solution

Step 1

Given,

Voltage of the battery $V = 9 V$

Energy $E = 1 \times 10^{5} J$

time $t = 6 h = (6 \times 3600) = 21600 s$

We know,

Energy $E = P . t$

And electric power $P = I . V$

So,

$E = I . V . t$ .....(1)

From Ohm's law we know,

$V = I R$

putting $I = \frac{V}{R}$ in equation (1) we get

$E = \frac{V^{2}}{R} t$

or, $R = \frac{V^{2} t}{E}$ .....(2)

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A resistor is connected across the terminals of a 9.0-V battery, which delivers 1.0 x 105 J of energy to the resistor in 6.0 hours. What is the resistance of the resistor? Number i Units