A researcher would like to know the proportion of the households that has a cable subscription. She gathered data from 90 households and found that 19 of them are cable subscribers. At a confidence level of 90 percent, determine the following: a. the sample proportion, ?̂ (p-hat) b. the ?̂  (q) c. the confidence interval of true proportion, p d. what should be the sample size if the margin of error E is to be 5%?

Q: You are a manager for a local convenience store. You want to determine what proportion of your…

A: We have given that,  Margin of error (E) = 5.50% and confidence level = 90% Then,  We will find the…

Q: d. FIND t a n = 10 for the 90% confidence interval for the mean. %3D

A: d. Given: n=10 α=0.1 The degrees of freedom is obtained as below: df=n-1=10-1=9 Critical value: The…

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d). A research…

A:

Q: In the measurement of support for one party, the sample data were n = 1300 and p̂ = 0.21. Compute a…

A: Given data: n = 1300  p̂ = 0.21. Confidence level = 95 %

Q: Kim wants to determine a 80 percent confidence interval for the true proportion of high school…

A: Given: Margin of error, E=0.04 Confidence level=80%

Q: C. Find the length of the confidence interval given the following data: 1.s = 4.5, n = 20,…

A: Here use formula of length of confidence interval

Q: Suppose you decide that you want to construct a 93% confidence interval. Which one of the following…

A: Given : confidence level, c = 93 %

Q: B. Find the margin error that corresponds to the given statistics and confidence level. n = 150, p =…

A:

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A:

Q: A new fertilizer was applied to the soil of 238 bean plants. 34% showed increased growth. Find the…

A: Given Information : A new fertilizer was applied to the soil of 238 bean plants. 34% showed…

Q: INSTRUCTION: Complete the table below by applying hypothesis testing in problem-solving. 1. A…

A:

Q: A researcher wishes to estimate the percentage of adults who support abolishing the penny. What size…

A: From the provided information, Margin of error (E) = 0.04 Confidence level = 90%

Q: The scores on a standardized test for 322 students in nontraditional math classes were compared to…

A: We have find given confidence interval..

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

A: We wish to construct a confidence interval for the mean height of male Swedes.The random variable…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A:

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A:

Q: A new fertilizer was applied to the soil of 222 bean plants. 28% showed increased growth. Find the…

A: Given Information: Sample Size, n =222Sample Proportion, p^=28% =0.28 To find out the margin of…

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d). A research…

A: The random variable X follows normal distribution. We have to construct 95% confidence interval.…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Given,   The sample proportion is,

Q: A Plitical pollster wants to know what proportion of voters think james burger should go away and…

A:

Q: The ACME computer company wanted to estimate the proportion of defective computers that are produced…

A: a) The interval (.024, .066) is the confidence interval for proportion of defectives. Thus the…

Q: Compare the results to those obtained in part (a). How does increasing the level of confidence…

A: simple random sample of size n is drawn. The sample mean is found to be 18.4   sample standard…

Q: USE THE INFORMATION BELOW TO ANSWER QUESTIONS 4 THRU 6 In 2020 researchers took random samples to…

A: Givenconfidence interval is (0.013 , 0.049)conficence level = 96%

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d).   A…

A: Given that  Sample size n=1002 and Favorable case x=585

Q: A new fertilizer was applied to the soil of 222 bean plants. 28% showed increased growth. Find the…

A:

Q: Mr. Price calculates a 95% confidence interval for the difference between the proportion of Aaron…

A: The 95% confidence interval for P Rodgers - P Mahomes is given as (-0.05, 0.15). When the repeated…

Q: The principal randomly selected six students to take an aptitude test. Their scores were 79 88 83 80…

A: " Since you have posted a question with multiple sub-parts, we will solve the first three subparts…

Q: 6) Find the t, value from Table for the indicated confidence level and sample size. 95% confidence…

A: a) 95% confidence level and n = 35 Degree of freedom = 35 – 1 = 34 Significance level(α) = 1-0.95 =…

Q: In each of Exercises, explain the effect on the margin of error and hence the effect on the accuracy…

A: Formula for the margin of error is given by

Q: Use the sample data and confidence level given below to complete parts (a) through (c). A research…

A:

Q: Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years…

A: p = 0.5 Margin of error = 0.01

Q: Cora wants to determine a 90% confidence interval for the true proportion of high school students in…

A: Confidence level=90%Margin of error(E)=0.02Assuming that we have no prior estimate of the proportion…

Q: A new fertilizer was applied to the soil of 151 bean plants. 72% showed increased growth. Find the…

A: The known values are, P^=0.72, n=151. Using Standard normal table, the critical value for two-tailed…

Q: You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You…

A: Suppose p is the true population proportion of workforce has two or more jobs.

Q: A new fertilizer was applied to the soil of 123 bean plants. 85% showed increased growth. Find the…

A: Find z-critical value: For the two-tail test, Area on each tail. Area to the left of the normal…

Q: (Q1). The principal randomly selected six students to take an aptitude test in her school. Their…

A:

Q: Suppose a 90 percent confidence interval to estimate a population proportion was calculated from a…

A: Solution: From the given information, the sample proportion is 18% and a margin of error is 4…

Q: Find the sample size, n, needed to estimate the percentage of adults who have consulted fortune…

A: Obtain the sample size of a preliminary estimate for p is 0.14.   The formula of sample size is,…

Q: If the population proportion is 0.7 . A researcher wants the margin of error to be 0.20 and the…

A: Given  pcap=0.7, Zcritical=1.96 at alpha=0.05 MOE=0.20

Q: Virginia wants to estimate the percentage of students who live more than three miles from the…

A: We have given that Margin of error (E) = 5% = 0.05Significance level (α) = 1 - 0.95 = 0.05 Hence,…