A researcher wishes to​ estimate, with 90​% ​confidence, the population proportion of adults who eat fast food four to six times per week. Her estimate must be accurate within 5​% of the population proportion. ​(a) No preliminary estimate is available. Find the minimum sample size needed. ​(b) Find the minimum sample size​ needed, using a prior study that found that 42​% of the respondents said they eat fast food four to six times per week. ​(c) Compare the results from parts​ (a) and​ (b).   What is the minimum sample size needed using a prior study that found that 42​% of the respondents said they eat fast food four to six times per​ week?   n=enter your response here   ​(Round up to the nearest whole number as​ needed.)

Q: you have been assigned the task of conducting a survey to study prescription medication purchases of…

A: Given: Confidence Level = 0.95

Q: According to a census company, 7.1% of all babies bon are of low birth weight. An obstetrician…

A: H0 : p = 0.071 H1 : p > 0.071   Observed value of low birth = 28 Observed value of not low birth…

Q: restaurant chain would like to measure the proportion of customers who are generally satisfied with…

A: Given: The sample number of customers that were surveyed is n=147. The number of customers who…

Q: In 1941, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you…

A: We have given that For the survey taken in 1941 n1 = 1100x1 = 374p̂ = x1/n1 = 151/429 = 0.3520 And…

Q: A company produces men’s jeans that can be styled with either a regular cut or a boot cut. In an…

A:

Q: A vaccine to prevent a severe virus was given to children within the first year of life as part of a…

A: a.It is given that x1=57, x2= 49, n1=3,294, n2= 1,648. .

Q: Nocaf Drinks, Inc., a producer of decaffeinated coffee, bottles Nocaf. Each bottle should have a net…

A: The provided information is as follows:The data set is given as: SampleSample RangeSample…

Q: A standardized exam consists of three parts: math, writing, and critical reading. Sample data…

A: (1)   Obtain the point estimate of the difference between the mean scores for the two tests.   The…

Q: 4% of the true proportion. A researcher wishes to estimate, with 90% confidence, the population…

A:

Q: A restaurant chain would like to measure the proportion of customers who are generally satisfied…

A: During a 1-week period, 147 customers were surveyed and 93% of them reported as being either…

Q: Group of answer choices The mean difference between the absorption rate of the reference drug and…

A: Null hypothesis is rejected if the p-value is less than the level of significance.    Here, p-value…

Q: A television sports commentator wants to estimate the proportion of citizens who​ "follow…

A: Solution: a. From the given information, confidence level is 0.96, p=0.48 and E=0.03.

Q: A researcher wishes to estimate, with 95% confidence, the population proportion of motor vehicle…

A:

Q: A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of motor vehicle…

A:

Q: A researcher wishes to estimate the number of households with two computers. How large a sample is…

A: given data   CI = 0.90, P ( - Z< P < Z ) = 0.90 therefore z = 1.645 ( =z table ) E = 6% =…

Q: A researcher wishes to estimate, with 90% confidence, the population proportion of motor vehicle…

A: The question is about sample size estimation Given : Confidence level = 0.90 Estimate is within 4 %…

Q: The American Academy of Pediatrics offers guidelines and recommendations for how much “screen time”…

A: Given data,No of parents n=200proportion of these parents who indicate they follow screen time…

Q: A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who…

A:

Q: Use the given data to find the minimum sample size required to estimate the population proportion.…

A: Ans - Given, Margin of error: E =  0.01;      confidence level: 95%; α = 1 - 0.95 = 0.05 Zα2  = 1.96…

Q: D. Construct a 95% confidence interval estimate of the proportion of adults believing that immediate…

A: It is given that  Favourable cases, X = 975 Sample size, n = 1762

Q: A researcher wishes to estimate, with 95% confidence, the population proportion of motor vehicle…

A: Given Data : Margin of error: ME = 0.03 confidence level: c= 0.95…

Q: A researcher wishes to estimate, with 95% confidence, the population proportion of motor vehicle…

A: The formula for sample size is :n=Zc2p(1-p)E2 Given : E = 2%=0.02 Confidence level = 95% Zc=1.96

Q: The Vegetarian Resource Group commissioned Harris Poll in 2016 to conduct a nationally…

A:

Q: A pool of 500 Houston residents indicated that 16% of them participated in Women’s March on January…

A:

Q: A researcher wishes to​ estimate, with 99​% ​confidence, the population proportion of motor vehicle…

A: The independent variable is motor vehicle fatalities that were caused by​alcohol-impaired driving.…

Q: A researcher wishes to estimate, with 90% confidence, the population proportion of motor vehicle…

A: Area on each tail for two-tail tests. Refer Standard normal table/Z-table OR use excel function…

Q: According to a census company, 7.1% of all babies born are of low birth weight. An obstetrician…

A: Here we conduct Z test for proprtion.

Q: In 1945, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you…

A: Let, X1= number of abstainer in the previous test n1= total sample size of the past test p1^ =…

Q: In the Star and Tribune newspaper, there is an article entitled “1 in 8 school buses fail tests."…

A: Given information: Sample of 200 buses and find that 20 buses fail the safety inspection. Let us…

Q: A television sports commentator wants to estimate the proportion of citizens who​ "follow…

A: Given Data: Margin of Error=0.22 p=0.54   z-value=1.96

Q: Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years…

A: p = 0.5 Margin of error = 0.01

Q: A newspaper infographic titled "Social Media Jeopardizing Your Job?" summarized data from a survey…

A: The following solution is provided below

Q: As chairperson of the Rogers County Task Force on Aging, you wish to estimate the proportion of…

A: Sample size n =44 Favorable cases x =22 Sample proportion p^=x/n  =22/44 =0.500

Q: A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of motor vehicle…

A: Given,margin of error(E)=0.03α=1-0.95=0.05α2 =0.025z0.025 =1.96

Q: 1950, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on…

A: In 1950, Total adults n1=1100                       x1=374 In recent year…

Q: Sample size. A pollster wishes to estimate,with 95% confidence, the proportion of people who believe…

A: It is given that margin of error (E) is 0.03 and the confidence level is 95%.

Q: (a) What is the minimum sample size needed assuming that no prior information is available? n =…

A:

Q: If we construct a 95% confidence interval estimate for the true proportion of all Minnesota school…

A: here given, n = 200 sample proportion  =20200 = 0.1 here for z-critical use excel command…

Q: Emma owns a toy store. If she wants to estimate the amount of revenue the company earns annually,…

A: We need to use the concept of sampling to solve this problem.

Q: a) What is the minimum sample size needed assuming that no prior information is available? O (Round…

A: When nothing is given assume p = 0.5

Q: question in a poll taken in 2007 asked, "Do you think the penalties for underage drinking should be…

A: Given data, n=500 p=61% =0.61 Construct a 95% confidence interval?

Q: A researcher wishes to​ estimate, with 99​% confidence, the population proportion of motor vehicle…

A: (a) Obtain the sample size of a no preliminary estimate for p. The formula of sample size is,   Use…

Q: A researcher wishes to​ estimate, with 90% ​confidence, the population proportion of adults who…

A: GivenMargin of Error(E)=0.02sample proportion(p^)=0.5α=1-0.90=0.10α2=0.05zα2=1.645