A researcher wishes to​ estimate, with 90​% ​confidence, the population proportion of adults who eat fast food four to six times per week. Her estimate must be accurate within 2​% of the population proportion. ​(a) No preliminary estimate is available. Find the minimum sample size needed. ​(b) Find the minimum sample size​ needed, using a prior study that found that 32​% of the respondents said they eat fast food four to six times per week. ​(c) Compare the results from parts​ (a) and​ (b).

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Q: A researcher wishes to estimate, with 95% confidence, the population proportion of adults who…

A:

Q: researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who…

A: Given that  Margin of error =E =0.04 95% confidence .

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Q: researcher wishes to​ estimate, with 90​% ​confidence, the population proportion of adults who…

A: Given that Margin of error =E=0.05 Population proportion 84% = 0.84 90% confidence.

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Q: A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who…

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Q: A researcher wishes to estimate, with 95% confidence, the population proportion of motor vehicle…

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Q: a. Express the original claim in symbolic form. Let the parameter represent the adults that would…

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Q: A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of motor vehicle…

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Q: A researcher wishes to estimate, with 90% confidence, the population proportion of motor vehicle…

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Q: A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who…

A:

Q: What is the minimum sample size needed assuming that no prior information is​ available? n= ___…

A: It is given that  Margin of error, E = 5% = 0.05 Confidence interval = 95%

Q: A researcher wishes to estimate, with 95% confidence, the population proportion of adults who…

A: It is given that margin of error (E) is 0.03 and the confidence level is 0.95.

Q: A researcher wishes to estimate, with 95% confidence, the population proportion of motor vehicle…

A: Given Data : Margin of error: ME = 0.03 confidence level: c= 0.95…

Q: A researcher wishes to estimate, with 95% confidence, the population proportion of motor vehicle…

A: The formula for sample size is :n=Zc2p(1-p)E2 Given : E = 2%=0.02 Confidence level = 95% Zc=1.96

Q: A researcher wishes to​ estimate, with 99​% ​confidence, the population proportion of motor vehicle…

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Q: A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who…

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Q: A researcher wishes to​ estimate, with 90​% ​confidence, the population proportion of adults who…

A:

Q: A researcher wishes to​ estimate, with 99​% ​confidence, the population proportion of adults who…

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Q: A researcher wishes to​ estimate, with 95​% confidence, the population proportion of adults who…

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Q: (a) No preliminary estimate is available. Find the minimum sample size needed. (b) Find the minimum…

A: Here use Margin of error formula

Q: A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of motor vehicle…

A: Given,margin of error(E)=0.03α=1-0.95=0.05α2 =0.025z0.025 =1.96

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Q: If we construct a 95% confidence interval estimate for the true proportion of all Minnesota school…

A: here given, n = 200 sample proportion  =20200 = 0.1 here for z-critical use excel command…

Q: a) What is the minimum sample size needed assuming that no prior information is available? O (Round…

A: When nothing is given assume p = 0.5

Q: A researcher wishes to​ estimate, with 90​% ​confidence, the population proportion of adults who…

A:

Q: A researcher wishes to​ estimate, with 99​% confidence, the population proportion of motor vehicle…

A: (a) Obtain the sample size of a no preliminary estimate for p. The formula of sample size is,   Use…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.