A researcher wishes to estimate the proportion of adults who have high-speed Internet access. What size sample should be obtained if she wishes the estimate to be within 0.03 with 90% confidence if(a) she uses a previous estimate of 0.28?(b) she does not use any prior estimates?Click the icon to view the table of critical values.(a) n=(Round up to the nearest integer.)(b) n=(Round up to the nearest integer.)Table of critical valuesCritical Value, zę• Level of Confidence,(1 - a)· 100%Area in Each Tail,90%0,051.64595%0.0251.9699%0.0052.575PrintDoneO Time Remaining:MacBook ProG Search or type URLesc

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Answered: A researcher wishes to estimate the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. Suppose a sample of 2552 tenth graders is drawn. Of the students sampled, 2119 read above the eighth grade level. Using the data, estimate the proportion of tenth graders reading at or below the eighth grade level. Enter your answer as a fraction or a decimal number rounded to three decimal places.
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 1000 supermarket shoppers revealed that 272 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Round your answer to four decimal places.)(b) Find a 95% confidence interval for p. (Round your answers to three decimal places.) lower limit upper limit What is the margin of error based on a 95% confidence interval? (Round your answer to three decimal places.)
Insurance companies are interested in knowing the population proportion of drivers who always buckle up before riding in a car.When designing a study to determine this population proportion, what is the minimum number of drivers you would need to survey to be 95% confident that the population proportion is estimated to within 0.05?
A drug company claims that their products’ contaminations never vary by more than 2%. Sample of 5 specimens were tested and the percentages of the purities are recorded as Observation no. 1 2 3 4 5 Percentages (%) 98.8 97.2 98.9 97.7 97.9 a. Do the sample data have enough proof to oppose the manufacturer's claim? (HINT: take the range of 2% equal 4o.) b. Find a 90% confidence interval for o?.
The formula used to calculate a confidence interval for the mean of a normal population when n is small is the following. xt (t critical value) √n What is the appropriate t critical value for each of the following confidence levels and sample sizes? (Round your answers to two decimal places.) USE SALT (a) 98% confidence, n = 17 (b) 90% confidence, n = 12 (c) 98% confidence, n = 24 (d) 90% confidence, n = 25 (e) 80% confidence, n = 13 (f) 95% confidence, n = 10
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. A random sample of 5616 physicians in Colorado showed that 3278 provided at least some charity care (i.e., treated poor people at no cost). A USE SALT (a) Let p represent the proportion of all Colorado physicians who provide some charity care. Find a point estimate for p. (Round your answer to four decimal places.) 0.5837 (b) Find a 99% confidence interval for p. (Round your answers to three decimal places.) lower limit 0.0617 upper limit
Solve A to C
f you want to be 99% confident of estimating the population proportion to within a sampling error of ±0.05 and there is historical evidence that the population proportion is approximately 0.42, what sample size is needed?
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 982 supermarket shoppers revealed that 262 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Round your answer to four decimal places.)(b) Find a 95% confidence interval for p. (Round your answers to three decimal places.) lower limit upper limit
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. A random sample of medical files is used to estimate the proportion p of all people who have blood type B. In USE SALT (a) If you have no preliminary estimate for p, how many medical files should you include in a random sample in order to be 85% sure that the point estimate p will be within a distance of 0.06 from p? Find the critical value for 85% confidence level, zo 85, and find the specified maximal error of estimate, E. (Round your answers to two decimal places.) Z0.85 E = Kour n = files (b) Answer part (a) if you use the preliminary estimate that about 10 out of 90 people have blood type B. (Round your proportions to three decimal places and your sample size up to the nearest whole number.) p = 1 - p = n = medical files
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 986 supermarket shoppers revealed that 268 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Round your answer to four decimal places.)(b) Find a 95% confidence interval for p. (Round your answers to three decimal places.) lower limit upper limit What is the margin of error based on a 95% confidence interval? (Round your answer to three decimal places.)
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 992 supermarket shoppers revealed that 274 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.) (b) Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)lower limit upper limit Give a brief explanation of the meaning of the interval. We are 95% confident that the true proportion of shoppers who stock up on bargains falls within this interval.We are 5% confident that the true proportion of shoppers who stock up on bargains falls above this interval. We are 5% confident that the true proportion of shoppers who…

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