**Question 8**A researcher was positioned at the side of a 2-lane rural highway. He recorded the volume of northbound traffic, aggregated into 15-minute intervals. The recorded volumes were 243, 276, 318, and 490 vehicles for the first, second, third, and fourth 15-minute intervals, respectively. Calculate the peak hour factor. Provide your answer to the nearest hundredths.**[Input Box]**Explanation of Concepts:- **Peak Hour Factor (PHF):** The PHF is a measure used in transportation engineering to assess traffic flow and helps determine the capacity and efficiency of roads. It indicates the variation of traffic volume within an hour.- **Calculation of PHF:** It can be calculated using the formula: \[ \text{PHF} = \frac{\text{Total hourly volume}}{4 \times \text{Peak 15-minute volume}} \]- **Interpreting Results:** A PHF closer to 1 indicates a consistent traffic flow over the hour, whereas a lower PHF suggests a highly variable flow with peaks.*This page may include interactive components for applying the concept.*

Given data:- The recorded volume were 243, 276, 318 and 490. Use formula:- PHF=V60490×Vnn ----(1)

A researcher was positioned at the side of a 2-lane rural highway. He recorded the volume of northbound traffic, aggregated into 15 minute intervals. The recorded volumes were 243, 276, 318 and 490 vehicles for the first, second, third, and fourth 15-minute intervals, respectively. Calculate the peak hour factor. Provide your answer to the nearest hundredths.

A researcher was positioned at the side of a 2-lane rural highway. He recorded the volume of northbound traffic, aggregated into 15 minute intervals. The recorded volumes were 243, 276, 318 and 490 vehicles for the first, second, third, and fourth 15-minute intervals, respectively. Calculate the peak hour factor. Provide your answer to the nearest hundredths.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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