**Study Analysis on News Station Viewing Time**A researcher is investigating whether the choice of news station impacts the duration of time (in minutes) people spend watching it. The data below represents survey responses:| Local | FOX | CNN ||-------|-----|-----|| 48 | 28 | 29 || 40 | 18 | 18 || 39 | 52 | 39 || 66 | 48 | 35 || 70 | 69 | 15 || 38 | 21 | 46 || 33 | 40 | 26 || 64 | 44 | 16 || 41 | 28 | - |Assumptions:- All distributions are normal.- Population standard deviations are equal.- Data is independently and randomly collected.- Significance level: \(\alpha = 0.05\).**Hypothesis:**- Null Hypothesis (\(H_0\)): \(\mu_1 = \mu_2 = \mu_3\)- Alternative Hypothesis (\(H_1\)): At least two means differ.**Analysis Steps:**1. **Study Type Selection:** - Select an appropriate answer regarding the study type.2. **Test-Statistic Calculation:** - Compute and enter the test-statistic value (accurate to 3 decimal places).3. **P-Value Calculation:** - Compute and enter the p-value (accurate to 4 decimal places).4. **Compare P-Value to \(\alpha\):** - Select an appropriate answer based on the p-value’s relationship to \(\alpha\).5. **Hypothesis Decision:** - Choose whether to accept or reject the null hypothesis.6. **Final Conclusion:** - Choose between: - Sufficient evidence exists to support the claim that the station is a factor in viewing time. - Insufficient evidence exists to support the claim.This analysis helps determine whether the news station affects the amount of time spent watching, providing insight into viewing behaviors.

Answer Given, Local FOX CNN 48 28 29 40 18 18 39 52 39 66 48 35 70 69 15 38 21 42 33 46 26 64 24 16 41 28____________________________________________Total 439 334 220____________________________________________________Mean 48.778 37.111 27.5____________________________________________________St.Dev. 14.043 17.316 10.569____________________________________________________SS 1577.556 2398.889 782____________________________________________________n = 9 9 8___________________________________________________Total sample size [N] =26DF [Total] = N-1 = 26-1 = 25DF [Between] = K-1 = 3-1 = 2DF [Within] = 25-2 = 23Test statistics [F] = [MS [between]]/[MS [Within]] = 966.797/ 206.889 = 4.673P-value:F.DIST.RT [4.673, 2, 23]= 0.0198P<0.05Reject the null hypothesis.There is sufficient evidence to conclude the claim that a station is a factor the amount of the time people watch the news.Final answer Test statistics [F] = 4.673P-value = 0.0198P<0.05Reject the H0,There is sufficient evidence to conclude the claim that a station is a factor the amount of the time people watch the news.