A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A random sample of 225 individua who had been taking the drug is questioned; 177 of them found relief from depression. Based upon this, compute a 95% confidence interval for the proport of all depressed individuals taking the drug who find relief. Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.)

Q: In the 2021-22 season, Klay Thompson made 114 out of 296 three point shots. Create a 95% confidence…

A: Solution: Given information: n= 296 Sample size  x= 114 successes p^=xn=114296=0.3851 Sample…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: A study found the temperature of 125 randomly selected healthy adults averaged 98.25 F with a…

A: It is given that sample mean is 98.25 and standard deviation is 0.733.

Q: A sample of 500 applications to a nursing programme included 400 applications from women with the…

A: Given Information: Sample size n=500 If 400 were applications from women, then 500-400=100…

Q: The 90% confidence interval is from to. (Round to three decimal places as needed.)

A: A poll of 1030 adults in a country was conducted by telephone. Of those surveyed, 139 had…

Q: In a sample of 290 adults, 191 had children. Construct a 95% confidence interval for the true…

A: 0.604 < p < 0.713 Explanation:Approach to solving the question:To construct a 95% confidence…

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: The CEO of a company wants to estimate the percent of employees that use company computers to go on…

A: Obtain the margin of error for a 95% confidence interval. The margin of error for a 95% confidence…

Q: Of 102 randomly selected adults, 42 were found to have high blood pressure. A 90% confidence…

A:

Q: According to a poll, 86% of California adults (434 out of 506 surveyed) feel that education is one…

A:

Q: st with 2440 subjects, 70% showed improvement from the old treatment. While in a clinical test with…

A: Given: Sample Proportion 1 (\hat p_1)(p^​1​) = 0.700.70 Sample Size 1 (N_1)(N1​) = 24402440…

Q: In a simple random sample of 1200 Americans age 20 and over, 138 of them were found to have Type I…

A: In a simple random sample of 1200 Americans age 20 and over, 138 of them were found to have Type I…

Q: In a study of 150 burglary incidents witnessed by the youngsters, 43% lead those young people…

A: The sample size is 150 and of which 43% lead those young people develop PTSD.

Q: A researcher wishes to estimate the proportion of adults in the city of St. George who are…

A: