A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A random sample of 225 individuals who had been taking the drug is questioned; 168 of them found relief from depression. Based upon this, compute a 90% confidence interval for the proportion of all depressed individuals taking the drug who find relief. Then find the lower limit and upper limit of the 90% confidence interval. Carry intermediate computations to at least 3 decimal places. Round answers to 2 decimal places.

Q: The distribution of Master's degrees conferred by a university is listed in the table. Frequency 216…

A: Answer Major                         FrequencyMathematics                   216English…

Q: test. It was found that 80 of them scored higher than 100. Based on this, compute a 95% confidence…

A: According to the given information in this question We need to construct 95% confidence interval

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

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Q: If n=30, ¯xx¯(x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n = 10, ¯xx¯ = 43, and s = 8, construct a confidence interval at a 90% confidence level. Assume…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: If n=30, (x-bar)=38, and s=8, construct a confidence interval at a 90% confidence level. Assume the…

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Q: A poll of n = 500 randomly selected elementary school students resulted in 110 of them stating…

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Q: If n=22, ¯xx¯(x-bar)=45, and s=4, construct a confidence interval at a 90% confidence level. Assume…

A: Ans -   Given the level of confidence interval   90 %                      Then   α = 1 - 0.90 =…

Q: If n=31, (x-bar)=49, and s=3, construct a confidence interval at a 80% confidence level. Assume the…

A: Given, Sample size = 31 Sample mean = 49 Sample standard deviation = 3   Since the population…

Q: If n=15, ¯xx¯(x-bar)=30, and s=2, construct a confidence interval at a 98% confidence level. Assume…

A: Given Sample size n = 15  degree of freedom = n-1 =14 x the level of confidence interval   98 %…

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: If n = 28, ¯xx¯ = 49, and s = 19, construct a confidence interval at a 90% confidence level. Assume…

A: Given information- Sample size, n = 28 Sample mean, x-bar = 49 Sample standard deviation, s = 19…

Q: If n=12, (x-bar)=33, and s=16, construct a confidence interval at a 80% confidence level. Assume the…

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Q: If n = 25, ¯x = 50, and s = 19, construct a confidence interval at a 99% confidence level. Assume…

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Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: According to a report on consumer fraud and identity theft, Indiana had 1671 complaints of identity…

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Q: If n = 15, ¯x = 50, and s = 9, construct a confidence interval at a 90% confidence level. Assume the…

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Q: Suppose that you will be taking a random sample from a population and that you intend to find a 95%…

A: Solution: The confidence interval for the population mean is calculated by using the following…

Q: Scientists tested each in a sample of 6 alleles of antigen-produced protein for level of peptide.…

A: The sample size n=6 The sample mean x¯=1.54 The sample standard deviation s=0.13 The confidence…

Q: Hearts College found that 50 students out of a sample of 600 students take the subway to school.…

A: Given data is fit for difference of proportions. we need to find the confidence interval for 90%.

Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: A sample of 700 from population A has a proportion of interest of 0.24 while a sample of 600 from…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: Construct the 90% confidence interval for the difference p1-p2 when x1=45, n1=85, x2=20, and n2=65.…

A: Given Information: x1=45n1=85x2=20n2=65c=90%=0.90

Q: If n = 15, the sample mean = 150, SD = 10, what is the confidence interval (using 99% confidence…

A: Given data,n=15x=150σ=10z-value at 99% confidence is Zc=2.576

Q: What proportion of Law School applicants are accepted into Law School? In a survey of a random…

A: According to the given information in this question  We can say that the We are 95% confident the…

Q: If n=14, (x-bar)=46, and s=18, construct a confidence interval at a 80% confidence level. Assume the…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: If n = 15, ¯xx¯ = 43, and s = 11, construct a confidence interval at a 98% confidence level. Assume…

A: Given that, The degree of freedom is, Critical values: The t-critical values for a two-tailed…

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

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Q: of 100 people sampled, 50 had kids. The best point estimate for p is. The margin of error for a 90%…

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Q: f n=19, sample mean=50, and s =8, construct a confidence interval at a 99% confidence level. Assume…

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Q: If n = 530 and X = 424, construct a 99% confidence interval for the population proportion, p. Give…

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Q: A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a…

A: Given information Sample proportion = 0.36 Sample size (n) = 1100

Q: An investment analyst collects data on stocks and notes whether or not dividend were paid and…

A: Given that: Pvice  No price  Tofal  increase  inclease 40751158748135127123250

Q: If n=25, z-46, and s=5, construct a confidence interval at a 95% confidence level. Assume the data…

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Q: Suppose that you will be taking a random sample from a population and that you intend to find a 95%…

A: If the sample size increases, then the standard error of statistic decreases. The margin of error is…

Q: Find a Confidence interval for the true Population Proportions if n = 30,        x = 75, and the…

A: From the given information, X=75 and n=30.

Q: Which one of the following statements about confidence intervals is false?   Given the same sample…

A: In this case, we need to identify the false statement for confidence interval.

Q: If n = 100 and p̂ (p-hat) = 0.4, construct a 95% confidence interval.

A: To find the 95% confidence interval for the population proportion. Given that,…

Q: If n=13, ¯xx¯(x-bar)=37, and s=9, construct a confidence interval at a 80% confidence level. Assume…

A: Givenn =13x = 37s=9confidence interval =80%

Q: A national organization conducted a survey of 1300 American adults and asked how many hours they…

A: Let X be the number of hours an American adult work each week.Given,

Q: Suppose we wish to construct a 95% confidence interval for the population proportion of fans in…

A: Given that, Total fans = 200 130 answered yes 95% confidence level

Q: If n=21, (x-bar)=37, and s=3, construct a confidence interval at a 90% confidence level. Assume the…

A: Given Information: Sample size n=21 Sample mean x¯=37 Sample standard deviation s=3 Confidence level…

Q: You are comparing men and women on hours spent watching TV. You pick a sample of 12 men and 14 women…

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Q: If n = 11,(x -bar)= 31, and s = 19, construct a confidence interval at a 99% confidence level.…

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Q: According to a poll, 86% of California adults (434 out of 506 surveyed) feel that education is one…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.