A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A randomsample of 225 individuals who had been taking the drug is questioned; 166 of them found relief from depression. Based upon this,compute a 95% confidence interval for the proportion of all depressed individuals taking the drug who find relief. Then find the lower limitand upper limit of the 95 % confidence interval.Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult alist of formulas.)Lowerlimit:Upperlimit:

Answered: Image /qna-images/answer/56f1b2a8-9425-46e0-be60-cc364fef33d4.jpg

Answered: A researcher wants to estimate the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose we wish to construct a 95% confidence interval for the population proportion of fans in Notre Dame Stadium on a football Saturday who traveled in their own car. When we asked 200 randomly selected fans, 130 answered yes. Calculate the margin of error for this interval. Round your answer to 3 decimal places.
A recent study of over 1000 parents on cyberbullying showed that a 95% confidence interval of proportion of kids who faced bullying in social media sites and apps is (0.122, 0.194). Find the point estimator of the population proportion of kids who faced bullying in social media sites and apps. Round your answer to three decimal places.
In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p <
According to a poll, 86% of California adults (434 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California. Find a 90% confidence interval for the population proportion. (Round your answers to three decimal places.) X * Enter a number.
In a survey conducted to 415 people it was found that they had walked 5000 meters on average for the past week. If s= 900, solve for the 95% confidence interval of the mean for all the respondents.
A Gallup survey of 2324 adults (at least 18 years old) in the U.S. found that 417 of them have donated blood in the past two years. Construct a 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years. Round your answer to three decimal places. Use Z = 1.645. Use the unrounded values in Excel to find the answers to #2, #3 and #4 1. Find the sample proportion of adults in the U.S. who have donated blood in the past two years. Round your answer to three decimal places. 2. The standard error for sample proportion has a value of V 3. The margin of error has a value of 4. Construct the 90% confidence interval for adults who have donated blood in the past t
Alfredo wants a 85% confidence interval for the true average gas mileage for a Gremlin after randomly sampling 9 Gremlins. It is known that the true sigma for Gremlin gas mileage is 4 mpg, and the average of the 9 Gremlins in Alfredo's study was 24 mpg. Find the confidence interval assuming the distribution is normal.
A study investigated ways to prevent staph infections in surgery patients. The researchers examined a random sample of 100 patients admitted to various hospitals for surgery. They found that 53 of these patients tested positive for Staphylococcus aureus, a bacterium responsible for most staph infections. Construct a 80% confidence interval for the proportion of all patients admitted for surgery who are carriers of S. aureus. Round your answers to three decimal places, and use four decimal places for any interim calculations. We are 80% confident that the interval ( of all patients admitted for surgery who are carriers of S. aureus. contains the true population proportion p
One scientist wondered if there was a difference in the average daily intake of dairy products between men and women. He took a sample of n1 = 50 adult men and n2 = 50 adult women and recorded their daily intake of dairy products in grams per day. A summary of the sample results is presented in the table. Construct a 95% confidence interval for the difference in the average daily intake of dairy products for men and women. Can it be concluded that there is a difference in the average daily intakes for men and women?
You want to get a 90% confidence interval for the difference between the percentage of females with red hair compared to males with red hair. You sample 76 females and find 34 of them have red hair. You sample 65 males and find 33 have red hair. < p1−p2 <
We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 34 had kids. Based on this, construct a 90% confidence interval for the proportion, p, of adult residents who are parents in this county. Give your answers as decimals, to three places.
A random sample of 212 high school students in a particular town showed that 56 smoke on a regular basis. Find the 95% confidence interval estimating the population percentage for smokers at this high school. Suppose the national average for smokers in high schools is 34.2%. Does it appear that the students in this particular town smoke less than the national average? Justify your answer

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