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A researcher wanted to study the tendency of our choices to be influenced by our environment, so s an experiment. The researcher recruited 90 volunteers. She randomly assigned 30 to sit in a room v 30 to sit in a room with yellow walls, and 30 to sit in a room with orange walls. After sitting in the roo mundane activities, she offered them all a snack of strawberries, bananas, or oranges. For each ind recorded which room the participant was in and which snack they chose. The data are displayed in Color Red Yellow Orange Strawberries 16 7 Snack Type Bananas 10 16

A researcher wanted to study the tendency of our choices to be influenced by our environment, so s an experiment. The researcher recruited 90 volunteers. She randomly assigned 30 to sit in a room v 30 to sit in a room with yellow walls, and 30 to sit in a room with orange walls. After sitting in the roo mundane activities, she offered them all a snack of strawberries, bananas, or oranges. For each ind recorded which room the participant was in and which snack they chose. The data are displayed in Color Red Yellow Orange Strawberries 16 7 Snack Type Bananas 10 16

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A researcher wanted to study the tendency of our choices to be influenced by our environment, so she conducted an experiment. The researcher recruited 90 volunteers. She randomly assigned 30 to sit in a room with red walls, 30 to sit in a room with yellow walls, and 30 to sit in a room with orange walls. After sitting in the room doing mundane activities, she offered them all a snack of strawberries, bananas, or oranges. For each individual, she recorded which room the participant was in and which snack they chose. The data are displayed in the table. Color Red Yellow Orange Strawberries 16 7 Snack Type Bananas 10 16 9. Oranges 4 7 12 The researcher would like to know if these data provide convincing evidence that the distribution of snack choice differs for the various room colors in the population of all volunteers like these. The random condition is met. The 10% condition is not needed because random sampling did not take place. This table of expected counts shows that all expected counts are at least 5.
Transcribed Image Text:A researcher wanted to study the tendency of our choices to be influenced by our environment, so she conducted an experiment. The researcher recruited 90 volunteers. She randomly assigned 30 to sit in a room with red walls, 30 to sit in a room with yellow walls, and 30 to sit in a room with orange walls. After sitting in the room doing mundane activities, she offered them all a snack of strawberries, bananas, or oranges. For each individual, she recorded which room the participant was in and which snack they chose. The data are displayed in the table. Color Red Yellow Orange Strawberries 16 7 Snack Type Bananas 10 16 9. Oranges 4 7 12 The researcher would like to know if these data provide convincing evidence that the distribution of snack choice differs for the various room colors in the population of all volunteers like these. The random condition is met. The 10% condition is not needed because random sampling did not take place. This table of expected counts shows that all expected counts are at least 5.
Color Red Yellow Orange Strawberries 10.67 10.67 10.67 Snack Type Bananas 11.67 11.67 11.67 Oranges 7.67 7.67 7.67 What is the value of the chi-square test statistic and P-value of this test? Find the chi-square table here. = 10.90. The P-value is between 0.02 and 0.025. x² = 10.90. The P-value is between 0.20 and 0.25. = 11.25. The P-value is between 0.02 and 0.025. x² = 11.25. The P-value is between 0.20 and 0.25.
Transcribed Image Text:Color Red Yellow Orange Strawberries 10.67 10.67 10.67 Snack Type Bananas 11.67 11.67 11.67 Oranges 7.67 7.67 7.67 What is the value of the chi-square test statistic and P-value of this test? Find the chi-square table here. = 10.90. The P-value is between 0.02 and 0.025. x² = 10.90. The P-value is between 0.20 and 0.25. = 11.25. The P-value is between 0.02 and 0.025. x² = 11.25. The P-value is between 0.20 and 0.25.
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