A researcher thinks he has developed a new technique to reduce proof-reading errors. Eleven volunteers from a publishing firm practice the technique for a week and then they are asked to proofread a 10-page document. Errors on this test were compared to their errors prior to practicing the new technique. Evaluate the results of her data using α = .051tail. **Attached Image** a. Show how the 95% confidence interval was calculated. b. State the conclusion in APA format.

Q: during production of detergent. In people with no lung dysfunction, a typical air flow rate is 0.80.…

A: As the population standard devoation is known, we will use z distribution. The value of z at the…

Q: We have presented a confidence interval (CI) for the difference, μ1 − μ2, between two population…

A: The 90% confidence interval is from –10 to –5. The 90% confidence interval for the mean of the…

Q: If n = 100 and p (p-hat) = 0.9, construct a 95% confidence %3D interval. Give your answers to three…

A: Givensample size(n)=100p^=0.9α=1-0.95=0.05α2=0.025zc=zα2=z0.025=1.96   (from z table)

Q: We have developed a new drug used to reduce fever and want to test its efficacy. Ten ER patients who…

A: First temperature : mean = 101.97 variance = 1.09 Second temperature : mean = 90.14 variance =…

Q: The caffeine content (in mg) was examined for a random sample of 50 cups of black coffee dispensed…

A:

Q: If n = 600 and p (p-hat) = 0.7, construct a 95% confidence interval. Give your answers to three…

A: It is given that, n = 600 and p (p-hat) = 0.7. we have to find the 95% confidence interval for true…

Q: We have presented a confidence interval (CI) for the difference, μ1 − μ2, between two population…

A: It is given that the 99% confidence interval for the difference between two population  means is…

Q: You surveyed business travelers to develop quality ratings for an airport. The maximum possible…

A: Given,sample size(n)=25sample mean(x¯)=6.34sample standard deviation(s)=2.16degrees of…

Q: A doctor wants to estimate the mean HDL cholesterol of all​ 20- to​ 29-year-old females. How many…

A: The formula for the sample size is as follows:

Q: Express the confidence interval mathematically. Do not round answers.

A: Let  be the population mean number of hours adults work each week.Given that,Sample size Sample mean…

Q: Part A: Make a 90% confidence interval for given that you have a sample of size 49 which produced a…

A: Given,margin of error(E)=0.2standard error(σ)=3.2α=1-0.90=0.10α2=0.05Z0.05=1.645      (from Z-table)

Q: Among a random sample of 400 restaurant workers, we find that 6.25% of workers have been working at…

A:

Q: A study investigated ways to prevent staph infections in surgery patients. The researchers examined…

A: From the provided information, Sample size (n) = 100 From which 88 patients tested positive for…

Q: A Harris Poll in 2003 asked a national sample of 2316 adults whether they favored or opposed…

A: The random variable opposing follows binomial distribution. The sample size is 2316. The value of…

Q: A study investigated ways to prevent staph infections in surgery patients. The researchers examined…

A: Given that, x=86,n=100 The sample proportion is, p^=xn  =86100  =0.86

Q: A researcher from a national reading program conducted a poll of 650 American adults over the age of…

A: Mean()=13.5Margin of error(E)=1.25sample size(n)=650confidence level=95%

Q: In a test of physical fitness, a fitness trainer for a group of men ages 65 and older from a local…

A: The population mean is known to be 20. Based on the sample evidence you have to test whether the…

Q: A recent poll indicated that 42% of men supported raises taxes to fund additional park services.…

A:

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: If a 90% confidence interval for µ is [15, 25],  then X=?, e=?

A: Note: Hello! Thank You for the question. We are considering 'e' as margin of error. From the given…

Q: A study investigated the effectiveness of meditation training in reducing trait anxiety. The study…

A: Given : n = 27 mean = 4.7 standard deviation = 6.8

Q: A random sample of 136 attorneys have mean IQ score of 109.2 and standard deviation IQ score 15. The…

A: From the given information, Sample size (n) = 136 Sample mean (M) = 109.2 Sample standard deviation…

Q: the sample proportion of females is  x=118  n=164 P = .720  #1 Make a 95% confidence interval for…

A:

Q: For each scenario below, decide if it would be appropriate to use (1) Critical z-values or (2)…

A: Solution To find the confidence interval we will use Excel According to the guidelines we solve only…

Q: A study found a confidence interval on the proportion of children that are hearing impaired was 0.04…

A: Given confidence interval is 0.04 to 0.16 i.e., p-E=0.04 -->1 p+E=0.16 -->2

Q: Which section of the course did better on the GRE Math exam after the course – the one with homework…

A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: A recent poll indicated that 42% of men supported raises taxes to fund additional park services.…

A: Given The data is as follows: Sample proportion of men, p^1=0.42 Sample proportion of women,…

Q: A recent poll indicated that 42% of men supported raises taxes to fund additional park services.…

A: The question is about confidence interval Given : Sample prop. of men supported raises taxes to fund…

Q: 17.18  4S overall mortality. The 4S study introduced in Exercise 17.17 also tallied deaths due to…

A:

Q: A study investigated ways to prevent staph infections in surgery patients. The researchers examined…

A: given data  n = 100 x = 86 80% ci for p.  p^ = xn = 86100 = 0.86

Q: If n = 140 and p (p-hat) = 0.8, construct a 95% confidence interval. %3D Give your answers to three…

A: We want to find the 95% CI for population proportion

Q: company manufactures a certain over-the-counter drug. The company samples 80 pills and finds that…

A: We have given that  Sample size n = 80 Sample mean = 325.5 Standard deviation s=10.3 90%confidence…

Q: A sample of 22 picture tubes is tested and the current needed to achieve the brightness is measured.…

A: We need to construct the 95%  upper end point of confidence interval for the population mean μ. The…

Q: A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol…

A: Mean difference (M) = 15.91 mg/dL Standard deviation of the mean difference (s) = 15.2714 mg/dL…

Q: A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol…

A: We have given information, The cholesterol levels for 27 patients were recorded before administering…

Q: A 90% confidence interval for the difference between the proportion of college students who use…

A:

Q: We have developed a new drug used to reduce fever and want to test its efficacy. Ten ER patients who…

A: Given Information: Ten ER patients who are running a fever agree to take the new drug instead of the…

Q: Part A: Construct and interpret a 95% confidence interval for the difference in population…

A: Let  is the difference between population proportions of females and males who have an after-school…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.