A researcher from UTM is interested in estimating p, the proportion of UTMstudents who are in favor of in-person classes in winter 2022. He divided thestudents into two strata: International and Domestic. The summary data aregiven in the following table.PopulationSizeSample Proportion: In favor ofin-person classesSample SizeDomesticN1 = 100001000Pi = 0.64InternationalN2 = 5000n2 = 500P2 = 0.52%3DFind a point estimate for p. Show all the steps. Circle the final answer.Place a bound on the error of estimation found in part (a). Show all thesteps. Circle the final answer.Estimate the total number of UTM students who are in favor of in-personclasses in winter 2021. Place a bound on the error of this estimation. Hint:Use parts (a) and (b). Show all the steps. Circle the final answer.Construct 95% confidence interval for the true proportion of UTMDomestic students who are in favor of in-person classes in winter 2021.Show all the steps. Circle the final answer.

Given information: Population size Sample size Sample proportion: In favor of in-person classes…

Answered: A researcher from UTM is interested in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which of the following data collection methods produces the highest level of evidence? Cross-sectional survey Case-control study Cohort study Systematic review
Find the (a) mean, (b) median, (c) mode, and (d) midrange for the given sample data. An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Listed below are the phenotype codes where 1 = smooth-yellow, 2=smooth-green, 3= wrinkled-yellow, and 4 = wrinkled-green. Do the results make sense? 3 1 3 2 2 4 2 1 3 3 3 2 1 3 (a) The mean phenotype code is (Round to the nearest tenth as needed.) (b) The median phenotype code is (Type an integer or a decimal.) (c) Select the correct choice below and fill in any answer boxes within your choice. OA. The mode phenotype code is (Use a comma to separate answers as needed.) OB. There is no mode. (d) The midrange of the phenotype codes is (Type an integer or a decimal.) Do the measures of center make sense? O A. Only the mode makes sense since the data is nominal. O B. All the measures of center make sense since the data is numerical. O C. Only the mean, median, and mode make sense since…
The midterm and final exam grades for a statistics course are provided in the data set below. Jaymes, a student in the class, scored 86 on both exams. Treat the given data sets as samples. Midterm: 80, 78, 85, 82, 79, 79, 78, 86, 80, 84, 78, 84, 80, 84, 81, 78, 81, 82, 78, 84 Final: 81, 88, 68, 69, 69 81, 82, 86, 76, 71, 72, 68, 77, 86, 68, 83, 84, 71, 81, 87 z-score for midterm: 1.857 z-score for final: 1.181 Based on the z-scores calculated above, which of Jaymes's grades is more unusual, the midterm grade or the final exam grade? Select the correct answer below: A. The absolute value of the z-score for the final exam grade is greater than for the midterm grade, so the final exam grade is more unusual. B. The absolute value of the z-score for the midterm exam grade is less than for the final grade, so the midterm grade is more unusual. C. The absolute value of the z-score for the midterm exam grade is greater than for the final grade, so the midterm grade is more…
RA company that manufactures car tires wants to compare breaking performance on dry and wet pavements for a brand of their tires. They selected a random sample of 10 sets of tires and put them on 10 cars. The stopping distance (ft) on dry pavement and wet pavement was recoded for each car. The results are summarized in the table below. Car 2. 4 8 9. 10 Dry 152 148 135 130 134 133 128 136 136 157 Wet 202 220 194 146 182 172 201 180 192 204 Do the data provide enough evidence to conclude that the average breaking performance is lower on wet naYement for this tire brand? Use the rejection point method. Use a 0.05.
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A randomly sampled group of patients at a major U.S. regional hospital became part of a nutrition study on dietary habits. Part of the study consisted of a 50-question survey asking about types of foods consumed. Each question was scored on a scale from one (most unhealthy behavior) to five (most healthy behavior). The answers were summed and averaged. The population of interest is the patients at the regional hospital. A prior survey of patients had found the mean score for the population of patients to be μ=2.9 After careful review of these data, the hospital nutritionist decided that patients could benefit from nutrition education. The current survey was implemented after patients were subjected to this education, and it produced the following sample statistics for the 15 patients sampled: x¯=3.5 and s=1.2 We would like to know if the education improved nutrition behavior. We test the hypotheses H0:μ=2.9 versus Ha:μ>2.9. The tt test to be used has the test statistic: Answer:
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In each part, give the value of the standardized statistic (z-score) for the sample mean. 100, σ = 8, n = 4 (a) x = 88, μ = Z = (b) x = 88, μ = 100, σ = 8, n = 64 Z = (c) x = 10.63, μ = 10.0, σ = 7, n = 10,000 z =

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