Finish the rest please A researcher claims that 29% of individuals who take a particular type of drug will develop side effects. Totest this claim, you form a random sample of 203 individuals who are taking this drug, of which 49developed side effects. Test the researcher's claim at a =0.01.a. Enter the null hypothesis for this test.Ho p0.29b. Enter the alternative hypothesis for this test.H₁: P0.29c. Is the original claim located in the null or alternative hypothesis?Null Hypothesisd. What is the test statistic for the given statistics?e. What is the p-value for this test?f. What is the decision based on the given statistics?Select an answerg. What is the correct interpretation of this decision?Using a % level of significance, there Select an answer sufficient evidence toSelect an answer the claim that 29% of individuals who take a particular type of drug will developside effects.

n=203 ,x=49, p=29% Sample proportion p^=x/n=49/203=0.2414(a) Null Hypothesis Ho: p=0.29(b) Alternate hypothesisH1: p≠0.29(c) Claim at Null hypothesisNull hypothesisd)Test statistic ( z )z = (p^ - p )∕√p(1 - p)/n= (0.2414- 0.29 )∕√0.29(1 - 0.29)/203= -1.53e)P-value =0.1260 , at two tailed test.(Calculated from excel)=2*(1-NORM.S.DIST(-1.53, TRUE))f)Decision:-P-value = 0.1260 > ?= 0.01 so Fail to reject the null hypothesis.g)Conclusion:Using a 1% level of significance, there is not sufficient evidence to reject the claim that 29% of individuals who take a particular type of drug will develop Select an answer side effects.d).test statistic Z =-1.53e)P-value=0.1260f)Fail to reject the null hypothesis.g)Conclusion:Using a 1% level of significance, there is not sufficient evidence to reject the claim that 29% of individuals who take a particular type of drug will develop Select an answer side effects.