Need part A 186 incorrect A report just came out that stated that 24.9% of all Americans say that vanilla is their favorite ice cream,22.9% say that chocolate is their favorite, 9.7% favor butter pecan, 9.6% favor strawberry, and the resthave other favorites. An ice cream shop owner thinks that her customers are not like the rest of America.The table below shows the results of 930 of her patrons ice cream selections. What can be concluded atthe ax = 0.05 significance level?a. Complete the table by filling in the expected frequencies. Round your answers to the nearest wholenumber.Frequencies of Favorite Ice CreamOutcome Frequency Expected FrequencyVanilla 227Chocolate 228Butter Pecan 107Strawberry 85Other283b. What is the correct statistical test to use?Select an answer Vc. What are the null and alternative hypotheses?Ho:Favorite ice cream and where the ice cream is purchased are dependent.Favorite ice cream and where the ice cream is purchased are independent.The distribution of favorite ice cream for customers at her shop is the same as it is forAmericans in general.O The distribution of favorite ice cream for customers at her shop is not the same as it is forAmericans in general.H₁:O Favorite ice cream and where the ice cream is purchased are independent.The distribution of favorite ice cream for customers at her shop is not the same as it is forAmericans in general.The distribution of favorite ice cream for customers at her shop is the same as it is forAmericans in general.Favorite ice cream and where the ice cream is purchased are dependent.d. The degrees of freedom =e. The test-statistic for this data =f. The p-value for this sample=(Please show your answer to three decimal places.)(Please show your answer to four decimal places.)

The proportion of the different types of favorite ice cream for American people is given below.OutcomesExpected percentageVanilla0.249Chocolate0.229Butter Pecan0.097Strawberry0.096Other0.329[calculate the Expected percentage of other is 1-(sum of reaming Expected percentage)]The formula for expected frequency is Expected frequency = Expected percentage * Total countwhere total count =930Outcomes FrequencyExpected percentageExpected frequencyVanilla2270.2490.249x930=231.57232Chocolate2280.2290.229x930=212.97213Butter Pecan1070.0970.097x930=90.2190Strawberry850.0960.096x930=89.2889Other2830.3290.329x930=305.97306Total 9301930a) The calculated expected frequency are,Outcomes FrequencyExpected FrequencyVanilla227232Chocolate228213Butter Pecan10790Strawberry8589Other283306Total 930930