A relation R exists such that for every input(x) is 2x. Is relation R a function, and why (20 Points) O The relation is not a function because there is only on output for each input. The relation R is not a function because there are two outputs for each input. The relation R is a function because there is only one output for each input. There is not enough information to determine whether relation R is a function.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A relation R exists such that for every input (x) is 2x. Is relation R a function, and why?
a Search the web.
* forms.office.com/Pages/ResponsePage aspx?id-JYyjinq200WpZ93WO6zK Ir-4pWPIlpHHp0ChfrCP4LIUMFIGMFIQUEYAQZYSOEdUNktIOFBFWhRWCAu
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5.A relation R exists such that for every input(x) is 2x. Is relation R a function, and why?
(20 Points)
The relation is not a function because there is only on output for each input.
The relation R is not a function because there are two outputs for each input.
The relation R is a function because there is only one output for each input.
There is not enough information to determine whether relation R is a function.
Submit
pe here to search
O O
Transcribed Image Text:a Search the web. * forms.office.com/Pages/ResponsePage aspx?id-JYyjinq200WpZ93WO6zK Ir-4pWPIlpHHp0ChfrCP4LIUMFIGMFIQUEYAQZYSOEdUNktIOFBFWhRWCAu ws Vista Co. e Chrome Web Store G Gmait O YouTube 9Maps 18 5.A relation R exists such that for every input(x) is 2x. Is relation R a function, and why? (20 Points) The relation is not a function because there is only on output for each input. The relation R is not a function because there are two outputs for each input. The relation R is a function because there is only one output for each input. There is not enough information to determine whether relation R is a function. Submit pe here to search O O
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