A regression model to predict Y, the state burglary rate per 100,000 people, used the following four state predictors: X₁ = median age,X₂ = number of bankruptcies per 1.000 population, X3 = federal expenditures per capita (a leading predictor), and X4 = high schoolgraduation percentage.Click here for the Excel Data File(a) Using the sample size of 50 people, calculate the calc and p-value in the table given below. (Negative values should be indicatedby a minus sign. Leave no cells blank - be certain to enter "0" wherever required. Round your answers to 4 decimal places.)PredictorInterceptAgeMedBankruptFedSpendHSGrad%Answer is complete but not entirely correct.*calc5.2526-2.1764✔✔1.4101✔Coefficient4,198.5808-27.354017.4893-0.0124-29.0314SE799.339512.568712.40330.01767.1268-0.7045-4.0736p-value0.00000.03480.29350.48480.0002

Answered: Image /qna-images/answer/023d810a-3157-41d6-add8-b39a194a602f.jpg

Answered: A regression model to predict Y, the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An investigation of the properties of bricks used to line aluminum smelter pots was published in an article. Six different commercial bricks were evaluated. The life span of a smelter pot depends on the porosity of the brick lining (the less porosity, the longer the life span); consequently, the researchers measured the apparent porosity of each brick specimen, as well as the mean pore diameter of each brick. See the table. Apparent Porosity (y). Mean Pore Diameter (x). Click the icon to view the table. Data table Mean Pore Diameter Apparent Porosity (%) (micrometers) Brick Interpret the y-intercept of the line. Choose the correct answer below. 18.7 12.0 В 18.3 9.8 O A. The y-intercept is Bo- This value has no meaning because 0 is not in the observed range of the independent variable mean pore diameter. 16.3 7.3 6.9 5.4 O B. The y-intercept is Bo: For each unit increase in mean pore diameter, the mean porosity is estimated to increase by B0- 17.2 10.9 O C. There is not enough…
A random sample of 50 plants was selected from a field containing one-year-old plants of a variety of guayule, a plant species yielding rubber. Of the 50, 25 were classified as Normal (N), 14 were classified as Off-type (O) and 11 as Aberrant (A). The data on the following page show the percentage rubber content from each plant. Normal Off-type Aberrant 6.34 6.40 5.70 4.84 5.01 6.20 4.25 8.90 6.93 6.38 6.68 7.10 6.42 7.26 7.29 6.30 7.01 6-84 7.12 6.83 7.31 7.25 6.86 6.68 5.82 4.46 7.70 5.90 5.24 5.58 6.36 7.10 6.81 7.32 6.48 5.88 5.24 5.51 7.00 6.42 6.20 6.04 5.58 4.72 7.42 7-27 6.43 6-10 6-01 7.90 (a) Test the null hypothesis that there is no difference in mean rubber content between the three types of plant. (b) If the means of the distributions of each type of plant are denoted by N, PO and PA respectively, test the following particular null hypotheses: (i) EN = RA; (ii) Po=(PN + PA).
What is the relative frequency of deaths that occurred in 2000 or before?
Refer to the data presented in Exercise 2.86. Note that there were 50% more accidents in the 25 to less than 30 age group than in the 20 to less than 25 age group. Does this suggest that the older group of drivers in this city is more accident- prone than the younger group? What other explanation might account for the difference in accident rates?
The trend of thinner beauty pageant winners has generated charges that the contest encourages unhealthy diet habits among young women. Listed below are body mass indexes (BMI) for beauty pageant winners from two different time periods. Find the coefficient of variation for each of the two sets of data, then compare the variation. The coefficient of variation for the BMI's of beauty pageant winners from the 1920s and 1930s is %
Ride services are on the rise, such as Uber and Lyft. You wondered if the recent news reports of crime occurring with these ride services impacted the usage of them, especially with women. You decide to conduct a survey about ride service usage among male and female college students. The results showed that 19 males use ride services and 11 do not. While 12 females use ride services and 18 do not. Calculate the chi-square statistic:
The following regression is fitted using variables identified that could be related to student requestedloan amount, LOAN-AMT($) for returning students of a certain University. ????−??? = ? + ? ?????? + ? ???? + ? ????Where ACCEPT = the percentage of applicants that was accepted by the university, PREV = previous loan amount and OUTS =outstanding loan amountThe data was processed using MNITAB and the following is an extract of the output obtained:EXHIBIT 2Predictor Coef StDev T PConstant -26780 6115 * 0.000ACCEPT 116.00 37.17 3.14 0.003PREV -4.21 14.12 -0.30 **OUTS 70.85 15.77 4.49 0.000S = 2685 R-Sq = 69.6% R-Sq(adj) = 67.7%Analysis of VarianceSource DF SS MS F PRegression 3 808139371 269379790 37.37 0.00Residual Error 49 353193051 7208021Total 52 1161332421a)What is dependent and independent variables? b)Fully write out the regression equation c)What is the sample size used in this investigation? d)Fill in the blanks identified by ‘*’ and ‘**’. e)Is β significant, at the 5% level of…
From the graphs displayed, is there evidence to suggest that there is a positive linear relationship between Square Feet and Bathrooms, for the population of real estate represented by this sample? Be sure to provide numeric support in your answer.
Please show work in Excel.
5. An ecologist is studying the flower Iris versicolor. He measures the width and length of 100 petals of this flower from a large collection of specimens and obtains the following data. Width: AVG = 1.3 cm, SD = 0.2 cm Length: AVG = 4.3 cm, SD = 0.5 cm r = 0.65 One of the petals is at the 30th percentile of both width and length. Relative to all the petals at the 30th percentile width, this petal's length is (circle one) smaller than average about average larger than average Justify your answer using a written explanation and/or a diagram.
The data used is from college campuses. The variables used in the analysis below include: crime, total campus crime; enroll, total enrollment; police, employed officers. Use the estimated OLS models to answer the questions below: Model A: In(crime) = -6.631 + 1.270ln(enroll), (1.034) (.110) .5804 n = 97; R² = Model B: In(crime) = -4.794+.923ln(enroll) +.516ln(police), (.144) (.149) (1.112) n = 97; R² = .632 Using Model A, test the null hypothesis that elasticity of crime with respect to enrollment is unit elastic, i.e. equal to one (against a two-sided alternative). What is the conclusion of your test using a significance level of .01? Reject Fail to reject O Not enough information.

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