A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $30,000, a $125 gas card, or a $5 shopping card. To claim his or her prize, a prospective customer needed to present the flier at the dealership's showroom. The fine print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,729, the chance of winning the gas card was 1 out of 31,729, and the chance of winning the shopping card was 31,727 out of 31,729. Complete parts (a) through (d). a. How many fliers do you think the automobile dealership sent out? Assume there is one car and one gas card available. 31729 fliers b. Using your answer to (a) and the probabilities listed on the flier, what is the expected value of the prize won by a prospective customer receiving a flier? μ=$5.95 (Round to the nearest cent as needed.) c. Using your answer to (a) and the probabilities listed on the flier, what is the standard deviation of the value of the prize won by a prospective customer receiving a flier? a=$(Round to the nearest cent needed.)
A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $30,000, a $125 gas card, or a $5 shopping card. To claim his or her prize, a prospective customer needed to present the flier at the dealership's showroom. The fine print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,729, the chance of winning the gas card was 1 out of 31,729, and the chance of winning the shopping card was 31,727 out of 31,729. Complete parts (a) through (d). a. How many fliers do you think the automobile dealership sent out? Assume there is one car and one gas card available. 31729 fliers b. Using your answer to (a) and the probabilities listed on the flier, what is the expected value of the prize won by a prospective customer receiving a flier? μ=$5.95 (Round to the nearest cent as needed.) c. Using your answer to (a) and the probabilities listed on the flier, what is the standard deviation of the value of the prize won by a prospective customer receiving a flier? a=$(Round to the nearest cent needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $30,000, a $125 gas card, or a $5 shopping card. To claim his or her prize, a prospective customer needed to
present the flier at the dealership's showroom. The fine print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,729, the chance of winning the gas card was 1 out of 31,729, and the chance of winning the shopping card was
31,727 out of 31,729. Complete parts (a) through (d).
a. How many fliers do you think the automobile dealership sent out? Assume there is one car and one gas card available.
31729 fliers
O
b. Using your answer to (a) and the probabilities listed on the flier, what is the expected value of the prize won by a prospective customer receiving a flier?
μ = $5.95 (Round to the nearest cent as needed.)
c. Using your answer to (a) and the probabilities listed on the flier, what is the standard deviation of the value of the prize won by a prospective customer receiving a flier?
o= $(Round to the nearest cent as needed.)
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