Please help with EXPLANATION! The answer key says the answer is B. But I don't understand why 29. A refrigerator contains 4 cans of Coke, 5 cans of Pepsi and 2 cans of Sprite. If two cans of softdrink are chosen simultaneously and at random, what is the probability exactly one is a Cokeif both cans are different?b) 14/19c) 9/19) 18/55a) 30/55g) none of the othersd) 15/19e) 2855

Name: Please help with EXPLANATION! The answer key says the answer is B. But
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Please help with EXPLANATION! The answer key says the answer is B. But I don't understand why 29. A refrigerator contains 4 cans of Coke, 5 cans of Pepsi and 2 cans of Sprite. If two cans of softdrink are chosen simultaneously and at random, what is

Given data: The numbers of Coke cans are C=4. The numbers of Pepsi cans are P=5. The numbers of Sprite cans are S=2. The expression for the total number of cans is, n=C+P+S Substitute the given values in the above expression. n=4+5+2=11 Write the expression for the probability that exactly one is Coke can if two different cans are picked. P=CC1×PC1nC2+CC1×SC1nC2 Substitute the given values in the above expression. P=4C1×5C111C2+4C1×2C111C2=4!!×3!5!1!×4!11!2!×9!+4!!×3!2!1!×1!11!2!×9!=2055+855=2855 Thus, there is a 28/55 probability that exactly one is Coke can if two different cans are picked, so option (e) is correct.